∫Calc Practice

Velocity, acceleration and speed in space

Problem 9.314 · medium

A particle has position \( \displaystyle \mathbf r(t) = \left\langle t^{2}, t^{3}, t \right\rangle \). Find its velocity, acceleration and speed at \( \displaystyle t = 2 \).
  1. \[ \left[\begin{matrix}\frac{d}{d t} t^{2}\\\frac{d}{d t} t^{3}\\\frac{d}{d t} t\end{matrix}\right] = \left[\begin{matrix}2 t\\3 t^{2}\\1\end{matrix}\right] \]
    v = r′.✓ Proved
  2. \[ \left[\begin{matrix}\frac{d}{d t} 2 t\\\frac{d}{d t} 3 t^{2}\\\frac{d}{d t} 1\end{matrix}\right] = \left[\begin{matrix}2\\6 t\\0\end{matrix}\right] \]
    a = v′.✓ Proved
  3. \[ \sqrt{161} \]
    Speed = ‖v(2)‖.✓ Proved
Answer \( \mathbf v = \left\langle 4, 12, 1 \right\rangle,\ \mathbf a = \left\langle 2, 12, 0 \right\rangle,\ \text{speed} = \sqrt{161} \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0difference quotients of the position

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (error) — The solution fails to explicitly evaluate the velocity and acceleration vectors at t=2, which is required by the problem statement. It only computes the symbolic derivatives and the final speed magnitude, omitting the vector results <4, 12, 1> and <2, 12, 0>.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: fail (error) 2026-10-06 — The solution fails to explicitly evaluate the velocity and acceleration vectors at t=2, which is required by the problem statement. It only computes the symbolic derivatives and the final speed magnitude, omitting the vector results <4, 12, 1> and <2, 12, 0>.
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: fail (error) 2026-10-06 — The solution fails to explicitly evaluate the velocity and acceleration vectors at t=2, which is required by the problem statement. It only computes the general derivatives and the final speed, omitting the specific vector values for v(2) and a(2).

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/motion_in_space, checked 2026-10-06 with SymPy 1.14.0.