∫Calc Practice

Triple products and volumes

Problem 9.248 · easy

Find the volume of the parallelepiped determined by \( \displaystyle \left\langle -1, 4, 4 \right\rangle \), \( \displaystyle \left\langle 4, 3, -4 \right\rangle \) and \( \displaystyle \left\langle 1, -1, -1 \right\rangle \).
  1. \[ \left[\begin{matrix}-7\\0\\-7\end{matrix}\right] \]
    v × w.✓ Proved
  2. \[ -21 \]
    u·(v × w).✓ Proved
  3. The volume is the absolute value of the triple product.
    Reviewed
Answer \( 21 \)

Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the 3 × 3 determinant, computed by mpmath

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-05
  • gpt-oss:20b: pass 2026-10-05
  • qwen3.6:27b-mlx: fail (error) 2026-10-05 — The solution calculates the triple product as -21 but fails to explicitly apply the absolute value to obtain the final answer of 21. The stated answer is correct, but the derivation is incomplete.
  • gpt-oss:20b: pass 2026-10-05

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/triple_product, checked 2026-10-05 with SymPy 1.14.0.