∫Calc Practice

Cylindrical and spherical coordinates

Problem 9.216 · easy

Convert the rectangular point \( \displaystyle \left(0, -5, -1\right) \) to cylindrical coordinates with \( \displaystyle r > 0 \), \( \displaystyle 0 \le \theta < 2\pi \).
  1. \[ 5 \]
    r = √(x² + y²).✓ Proved
  2. \[ \left[\begin{matrix}0\\-5\end{matrix}\right] \]
    θ = 3*pi/2 puts the point in the right quadrant.✓ Proved
Answer \( \left(5, \frac{3 \pi}{2}, -1\right) \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0converted back to rectangular in floating point

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (error) — The solution fails to explicitly calculate or justify the value of theta, merely stating that 3pi/2 puts the point in the right quadrant without showing the arctan calculation or quadrant analysis. It also omits the trivial but necessary step of confirming z = -1.
Every verdict on record (4)
  • qwen3.6:27b-mlx: fail (error) 2026-10-04 — The solution fails to explicitly calculate or justify the value of theta, merely stating that 3pi/2 puts the point in the right quadrant without showing the arctan calculation or quadrant analysis. It also omits the trivial but necessary step of confirming z = -1.
  • gpt-oss:20b: pass 2026-10-04
  • qwen3.6:27b-mlx: fail (error) 2026-10-04 — The solution fails to explicitly calculate or justify the value of theta. It merely asserts that 3*pi/2 is in the right quadrant without showing the calculation (e.g., using arctan or analyzing signs of x and y) and ignores the requirement to ensure r > 0 and 0 <= theta < 2pi in the derivation steps.
  • gpt-oss:20b: pass 2026-10-04

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/cylindrical_spherical_coords, checked 2026-10-04 with SymPy 1.14.0.