Cross product
Problem 9.176 · easy
Find \( \displaystyle \mathbf{u} \times \mathbf{v} \) for \( \displaystyle \mathbf{u} = \langle -4, 1, 1 \rangle,\ \mathbf{v} = \langle 3, 0, -4 \rangle \), and the area of the parallelogram they span.
- Expand the determinant with rows i j k, u, v.Reviewed
- \[ \left[\begin{matrix}-4\\-13\\-3\end{matrix}\right] \]The components.Reviewed
- \[ \sqrt{194} \]Area = |u × v|.Reviewed
Answer \( \mathbf{u}\times\mathbf{v} = \langle -4, -13, -3 \rangle,\quad \text{area} = \sqrt{194} \)
Lines: 3 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | both sides are the same expression: the line states a value, and the working that produced it is not on the line |
| 3 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | both sides are the same expression: the line states a value, and the working that produced it is not on the line |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | Lagrange's identity √(|u|²|v|² − (u·v)²) gives the same area |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies the determinant method for the cross product and the magnitude formula for the area. The calculations are verified as correct.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly applies the determinant method for the cross product and the magnitude formula for the area. The calculations are verified as correct.gpt-oss:20b: pass 2026-10-04qwen3.6:27b-mlx: inconclusive 2026-09-29 — reviewer returned a non-objectgpt-oss:20b: pass 2026-09-29qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly identifies the method (determinant expansion for cross product) and the formula for area (magnitude of the cross product). The computed vector and magnitude are correct.gpt-oss:20b: pass 2026-09-29
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/cross_product_area, checked 2026-10-13 with SymPy 1.14.0.