Cross product
Problem 9.173 · easy
Find \( \displaystyle \mathbf{u} \times \mathbf{v} \) for \( \displaystyle \mathbf{u} = \langle -2, 3, -4 \rangle,\ \mathbf{v} = \langle 4, 1, 3 \rangle \), and the area of the parallelogram they span.
- Expand the determinant with rows i j k, u, v.Reviewed
- \[ \left[\begin{matrix}13\\-10\\-14\end{matrix}\right] \]The components.Reviewed
- \[ \sqrt{465} \]Area = |u × v|.Reviewed
Answer \( \mathbf{u}\times\mathbf{v} = \langle 13, -10, -14 \rangle,\quad \text{area} = \sqrt{465} \)
✓ Nihil obstat Lines: 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | both sides are the same expression: the line states a value, and the working that produced it is not on the line |
| 3 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | both sides are the same expression: the line states a value, and the working that produced it is not on the line |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | Lagrange's identity √(|u|²|v|² − (u·v)²) gives the same area |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the method for computing the cross product and the area of the parallelogram. The intermediate steps are algebraically verified, and the final results match the stated answer.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly identifies the method for computing the cross product and the area of the parallelogram. The intermediate steps are algebraically verified, and the final results match the stated answer.gpt-oss:20b: pass 2026-10-04qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly identifies the method for computing the cross product and the area of the parallelogram. The intermediate vector and final scalar result are correct.gpt-oss:20b: pass 2026-09-29qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly computes the cross product and its magnitude. The steps are logically sound and the final answer is correct.gpt-oss:20b: pass 2026-09-29
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/cross_product_area, checked 2026-10-13 with SymPy 1.14.0.