∫Calc Practice

Tangent lines to parametric curves

Problem 8.81 · hard

Find the equation of the tangent line to \( \displaystyle x = 2 t,\ y = 3 t + 1 \) at \( \displaystyle t = 2 \).
  1. dy/dx = (dy/dt)/(dx/dt).
  2. \[ \frac{d}{d t} 2 t = 2 \]
    dx/dt.✓ Proved
  3. \[ \frac{d}{d t} \left(3 t + 1\right) = 3 \]
    dy/dt.✓ Proved
  4. \[ \frac{3}{2} \]
    The slope at t = 2.
  5. \[ \left[\begin{matrix}4\\7\end{matrix}\right] \]
    The point.
  6. \[ \frac{3 x}{2} + 1 \]
    Point-slope form.
Answer \( y = \frac{3 x}{2} + 1 \)

Lines: 2 proved, 4 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Not checked—both sides are the same expression: the line states a value, and the working that produced it is not on the line
5Not checked—both sides are the same expression: the line states a value, and the working that produced it is not on the line
6Not checked—both sides are the same expression: the line states a value, and the working that produced it is not on the line
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0a secant through nearby points of the curve has the same slope; the line passes through the point

Reviewers

  • gpt-oss:20b: fail (misleading) — The final sentence claims to use point‑slope form but simply repeats the target equation without showing the step y‑7 = (3/2)(x‑4). It does not demonstrate how the point (4,7) is incorporated, which could mislead a student about the correct derivation.
  • qwen3.6:27b-mlx: pass — The solution correctly applies the chain rule for parametric equations, computes the derivatives and point coordinates accurately, and derives the correct tangent line equation.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly applies the chain rule for parametric equations, computes the derivatives and point coordinates accurately, and derives the correct tangent line equation.
  • gpt-oss:20b: fail (misleading) 2026-10-04 — The final sentence claims to use point‑slope form but simply repeats the target equation without showing the step y‑7 = (3/2)(x‑4). It does not demonstrate how the point (4,7) is incorporated, which could mislead a student about the correct derivation.
  • qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly applies the chain rule for parametric derivatives, calculates the slope and point at t=2, and derives the correct linear equation.
  • gpt-oss:20b: pass 2026-09-29
  • qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly applies the formula for the slope of a parametric curve and uses the correct point and slope to derive the tangent line equation.
  • gpt-oss:20b: pass 2026-09-29

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/parametric_tangent, checked 2026-10-13 with SymPy 1.14.0.