Tangent lines to parametric curves
Problem 8.73 · hard
Find the equation of the tangent line to \( \displaystyle x = e^{t},\ y = 3 t + 1 \) at \( \displaystyle t = -1 \).
- dy/dx = (dy/dt)/(dx/dt).
- \[ \frac{d}{d t} e^{t} = e^{t} \]dx/dt.✓ Proved
- \[ \frac{d}{d t} \left(3 t + 1\right) = 3 \]dy/dt.✓ Proved
- \[ 3 e \]The slope at t = -1.
- \[ \left[\begin{matrix}e^{-1}\\-2\end{matrix}\right] \]The point.
- \[ 3 e \left(x - e^{-1}\right) - 2 = 3 e x - 5 \]Point-slope form.✓ Proved
Answer \( y = 3 e x - 5 \)
Lines: 3 proved, 3 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | Not checked | — | both sides are the same expression: the line states a value, and the working that produced it is not on the line |
| 5 | Not checked | — | both sides are the same expression: the line states a value, and the working that produced it is not on the line |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | a secant through nearby points of the curve has the same slope; the line passes through the point |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (error) — Line 4 incorrectly calculates the slope at t = -1 as 3*E (3e) instead of 3/e. Consequently, the final equation is wrong.
Every verdict on record (6)
qwen3.6:27b-mlx: fail (error) 2026-10-03 — Line 4 incorrectly calculates the slope at t = -1 as 3*E (3e) instead of 3/e. Consequently, the final equation is wrong.gpt-oss:20b: pass 2026-10-03qwen3.6:27b-mlx: pass 2026-09-28gpt-oss:20b: pass 2026-09-28qwen3.6:27b-mlx: pass 2026-09-28 — The solution correctly applies the chain rule for parametric derivatives, evaluates the slope and point at t=-1, and derives the correct linear equation. The notation 'E' for e is consistent with the stated answer.gpt-oss:20b: pass 2026-09-28
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/parametric_tangent, checked 2026-10-13 with SymPy 1.14.0.