Tangent lines to parametric curves
Problem 8.45 · hard
Find the equation of the tangent line to \( \displaystyle x = \cos{\left(t \right)},\ y = t^{3} \) at \( \displaystyle t = \frac{\pi}{4} \).
- dy/dx = (dy/dt)/(dx/dt).Reviewed
- \[ \frac{d}{d t} \cos{\left(t \right)} = - \sin{\left(t \right)} \]dx/dt.✓ Proved
- \[ \frac{d}{d t} t^{3} = 3 t^{2} \]dy/dt.✓ Proved
- \[ - \frac{3 \sqrt{2} \pi^{2}}{16} \]The slope at t = \frac{\pi}{4}.Reviewed
- \[ \left[\begin{matrix}\frac{\sqrt{2}}{2}\\\frac{\pi^{3}}{64}\end{matrix}\right] \]The point.Reviewed
- \[ - \frac{3 \sqrt{2} \pi^{2} \left(x - \frac{\sqrt{2}}{2}\right)}{16} + \frac{\pi^{3}}{64} = - \frac{3 \sqrt{2} \pi^{2} x}{16} + \frac{\pi^{3}}{64} + \frac{3 \pi^{2}}{16} \]Point-slope form.✓ Proved
Answer \( y = - \frac{3 \sqrt{2} \pi^{2} x}{16} + \frac{\pi^{3}}{64} + \frac{3 \pi^{2}}{16} \)
✓ Nihil obstat Lines: 3 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | both sides are the same expression: the line states a value, and the working that produced it is not on the line |
| 5 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | both sides are the same expression: the line states a value, and the working that produced it is not on the line |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | a secant through nearby points of the curve has the same slope; the line passes through the point |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies the chain rule for parametric equations, computes the derivatives and point coordinates accurately, and derives the correct tangent line equation.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-09-28 — The solution correctly applies the chain rule for parametric equations, computes the derivatives and point coordinates accurately, and derives the correct tangent line equation.gpt-oss:20b: pass 2026-09-28qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly applies the chain rule for parametric curves, computes the derivatives and point coordinates accurately, and derives the correct tangent line equation.gpt-oss:20b: pass 2026-09-27qwen3.6:27b-mlx: pass 2026-09-26gpt-oss:20b: pass 2026-09-26
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/parametric_tangent, checked 2026-10-13 with SymPy 1.14.0.