∫Calc Practice

Horizontal and vertical tangents of parametric curves

Problem 8.380 · medium

Find the points where \( \displaystyle x = t^{3} - 6 t,\ y = t^{2} + 2 \) has a horizontal or a vertical tangent line.
  1. \[ \frac{d}{d t} \left(t^{3} - 6 t\right) = 3 t^{2} - 6 \]
    dx/dt.✓ Proved
  2. \[ \frac{d}{d t} \left(t^{2} + 2\right) = 2 t \]
    dy/dt.✓ Proved
  3. Horizontal tangent: dy/dt = 0 with dx/dt ≠ 0. Vertical: dx/dt = 0 with dy/dt ≠ 0.
    Reviewed
  4. \[ \left. 2 t \right|_{\substack{ t=0 }} = 0 \]
    t = 0: horizontal, at (0, 2).✓ Proved
  5. \[ \left. 3 t^{2} - 6 \right|_{\substack{ t=- \sqrt{2} }} = 0 \]
    t = -sqrt(2): vertical, at (4*sqrt(2), 4).✓ Proved
  6. \[ \left. 3 t^{2} - 6 \right|_{\substack{ t=\sqrt{2} }} = 0 \]
    t = sqrt(2): vertical, at (-4*sqrt(2), 4).✓ Proved
Answer \( \text{horizontal at } (0, 2);\ \text{vertical at } (4*sqrt(2), 4), (-4*sqrt(2), 4) \)

Lines: 5 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0roots of dx/dt and dy/dt found by Newton's method from a dense grid

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the conditions for horizontal and vertical tangents, solves for the parameter values, and correctly maps them to the Cartesian coordinates.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-18 — The solution correctly identifies the conditions for horizontal and vertical tangents, solves for the parameter values, and correctly maps them to the Cartesian coordinates.
  • gpt-oss:20b: pass 2026-10-18
  • qwen3.6:27b-mlx: fail (error) 2026-10-16 — The solution swaps the coordinates for the vertical tangents. At t = -sqrt(2), x = 4*sqrt(2) and y = 4, so the point is (4*sqrt(2), 4). At t = sqrt(2), x = -4*sqrt(2) and y = 4, so the point is (-4*sqrt(2), 4). The comments in lines 5 and 6 incorrectly assign these points to the wrong t-values.
  • gpt-oss:20b: pass 2026-10-16
  • qwen3.6:27b-mlx: fail (error) 2026-10-15 — The coordinates for the vertical tangents are swapped. At t = -sqrt(2), x = -4*sqrt(2), not 4*sqrt(2). At t = sqrt(2), x = 4*sqrt(2), not -4*sqrt(2).
  • gpt-oss:20b: pass 2026-10-15

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/parametric_tangent_hv, checked 2026-10-18 with SymPy 1.14.0.