Horizontal and vertical tangents of parametric curves
Problem 8.356 · medium
Find the points where \( \displaystyle x = \cos{\left(t \right)},\ y = \sin{\left(2 t \right)} \) for \( \displaystyle 0 \le t < 2\pi \) has a horizontal or a vertical tangent line.
- \[ \frac{d}{d t} \cos{\left(t \right)} = - \sin{\left(t \right)} \]dx/dt.✓ Proved
- \[ \frac{d}{d t} \sin{\left(2 t \right)} = 2 \cos{\left(2 t \right)} \]dy/dt.✓ Proved
- Horizontal tangent: dy/dt = 0 with dx/dt ≠ 0. Vertical: dx/dt = 0 with dy/dt ≠ 0.
- \[ \left. 2 \cos{\left(2 t \right)} \right|_{\substack{ t=\frac{\pi}{4} }} = 0 \]t = pi/4: horizontal, at (sqrt(2)/2, 1).✓ Proved
- \[ \left. 2 \cos{\left(2 t \right)} \right|_{\substack{ t=\frac{3 \pi}{4} }} = 0 \]t = 3*pi/4: horizontal, at (-sqrt(2)/2, -1).✓ Proved
- \[ \left. 2 \cos{\left(2 t \right)} \right|_{\substack{ t=\frac{5 \pi}{4} }} = 0 \]t = 5*pi/4: horizontal, at (-sqrt(2)/2, 1).✓ Proved
- \[ \left. 2 \cos{\left(2 t \right)} \right|_{\substack{ t=\frac{7 \pi}{4} }} = 0 \]t = 7*pi/4: horizontal, at (sqrt(2)/2, -1).✓ Proved
- \[ \left. - \sin{\left(t \right)} \right|_{\substack{ t=0 }} = 0 \]t = 0: vertical, at (1, 0).✓ Proved
- \[ \left. - \sin{\left(t \right)} \right|_{\substack{ t=\pi }} = 0 \]t = pi: vertical, at (-1, 0).✓ Proved
Answer \( \text{horizontal at } (sqrt(2)/2, 1), (-sqrt(2)/2, -1), (-sqrt(2)/2, 1), (sqrt(2)/2, -1);\ \text{vertical at } (1, 0), (-1, 0) \)
Lines: 8 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | Not checked | — | a sentence; read, not computed |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | roots of dx/dt and dy/dt found by Newton's method from a dense grid |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (error) — The solution fails to check the condition dx/dt != 0 for horizontal tangents. At t = 3*pi/4 and 7*pi/4, both dx/dt and dy/dt are zero, creating singular points (cusps) rather than smooth horizontal tangents. These points should be excluded or analyzed separately, but the solution lists them as standard horizontal tangents.
Every verdict on record (6)
qwen3.6:27b-mlx: fail (error) 2026-10-18 — The solution fails to check the condition dx/dt != 0 for horizontal tangents. At t = 3*pi/4 and 7*pi/4, both dx/dt and dy/dt are zero, creating singular points (cusps) rather than smooth horizontal tangents. These points should be excluded or analyzed separately, but the solution lists them as standard horizontal tangents.gpt-oss:20b: pass 2026-10-18qwen3.6:27b-mlx: pass 2026-10-16 — The solution correctly identifies the conditions for horizontal and vertical tangents and verifies that the non-zero derivative condition holds for all candidate points. The coordinates and parameter values are correct.gpt-oss:20b: pass 2026-10-16qwen3.6:27b-mlx: fail (error) 2026-10-14 — The solution fails to check the condition dx/dt ≠ 0 for horizontal tangents and dy/dt ≠ 0 for vertical tangents. At t = 0 and t = π, both dx/dt and dy/dt are zero, resulting in singular points (cusps) rather than vertical tangents. The solution incorrectly classifies these as vertical tangents.gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/parametric_tangent_hv, checked 2026-10-18 with SymPy 1.14.0.