∫Calc Practice

Conics in polar form

Problem 8.314 · medium

For the conic \( \displaystyle r = \frac{10}{4 \sin{\left(\theta \right)} + 3} \), find the eccentricity, identify the conic, and find the directrix.
  1. Divide top and bottom by the constant in the denominator to get r = ed/(1 ± e cos θ).
  2. \[ \frac{10}{3 \left(\frac{4 \sin{\left(\theta \right)}}{3} + 1\right)} = \frac{10}{4 \sin{\left(\theta \right)} + 3} \]
    The standard form.✓ Proved
  3. \[ \frac{\left|{4}\right|}{3} = \frac{4}{3} \]
    e = 4/3: > 1, a hyperbola.✓ Proved
  4. \[ \frac{10}{3 \cdot \frac{4}{3}} = \frac{5}{2} \]
    ed = 10/3, so d = 5/2.✓ Proved
Answer \( e = \frac{4}{3},\ \text{hyperbola},\ \text{directrix } y = 5/2 \)

Lines: 3 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0for points on the curve, distance to the focus over distance to the directrix is e

Reviewers

  • gpt-oss:20b: fail (error) — The first sentence incorrectly states the standard polar form as r = ed/(1 ± e cos θ) when the given equation involves sin θ. It should be r = ed/(1 ± e sin θ).
  • qwen3.6:27b-mlx: fail (error) — The solution fails to specify the orientation of the directrix. Since the denominator contains sin(theta), the directrix is horizontal (y = d), but the solution does not explicitly state this or distinguish it from a vertical directrix (x = d) which would result from cos(theta). Without this, the answer 'y = 5/2' is not justified by the steps shown.
Every verdict on record (6)
  • qwen3.6:27b-mlx: fail (error) 2026-10-17 — The solution fails to specify the orientation of the directrix. Since the denominator contains sin(theta), the directrix is horizontal (y = d), but the solution does not explicitly state this or distinguish it from a vertical directrix (x = d) which would result from cos(theta). Without this, the answer 'y = 5/2' is not justified by the steps shown.
  • gpt-oss:20b: fail (error) 2026-10-17 — The first sentence incorrectly states the standard polar form as r = ed/(1 ± e cos θ) when the given equation involves sin θ. It should be r = ed/(1 ± e sin θ).
  • qwen3.6:27b-mlx: fail (style) 2026-10-15 — [domain objection, downgraded to style] The solution fails to identify the directrix as horizontal (y = 5/2) because the denominator contains sin(theta), not cos(theta). It also omits the sign check required to determine if the directrix is above or below the pole.
  • gpt-oss:20b: fail (error) 2026-10-15 — The first sentence incorrectly assumes the standard polar form r=ed/(1±e cosθ) applies after dividing by the constant. The given denominator contains sinθ, so the correct form is r=ed/(1±e sinθ). This misidentification of the standard form leads to an incorrect identification of the directrix and the conic type.
  • qwen3.6:27b-mlx: pass 2026-10-14
  • gpt-oss:20b: fail (misleading) 2026-10-14 — The first sentence incorrectly states the standard polar form as r=ed/(1±e cosθ) when the given equation involves sinθ; this could mislead a student about the correct orientation of the conic.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/polar_conics, checked 2026-10-17 with SymPy 1.14.0.