Eliminating the parameter
Problem 8.224 · medium
Eliminate the parameter from \( \displaystyle x = 3 \sec{\left(t \right)},\ y = 3 \tan{\left(t \right)} \), and say what kind of curve it is.
- sec²t − tan²t = 1.
- \[ \left. \frac{x^{2}}{9} - \frac{y^{2}}{9} - 1 \right|_{\substack{ x=3 \sec{\left(t \right)}\\ y=3 \tan{\left(t \right)} }} = 0 \]The parametric point satisfies the equation for every t.✓ Proved
Answer \( \frac{x^{2}}{9} - \frac{y^{2}}{9} = 1\ (\text{hyperbola}) \)
Lines: 1 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | points on the parametric curve at four values of t satisfy the equation |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (style) — [domain objection, downgraded to style] The solution identifies the curve as a hyperbola but fails to specify the domain restrictions (x >= 3 or x <= -3). The parametric equations only trace the two branches of the hyperbola, not the entire curve defined by the Cartesian equation.
Every verdict on record (6)
qwen3.6:27b-mlx: fail (style) 2026-10-17 — [domain objection, downgraded to style] The solution identifies the curve as a hyperbola but fails to specify the domain restrictions (x >= 3 or x <= -3). The parametric equations only trace the two branches of the hyperbola, not the entire curve defined by the Cartesian equation.gpt-oss:20b: pass 2026-10-17qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly identifies the trigonometric identity needed to eliminate the parameter and verifies that the parametric equations satisfy the resulting Cartesian equation. The identification of the curve as a hyperbola is correct.gpt-oss:20b: pass 2026-10-15qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly identifies the trigonometric identity and verifies that the parametric equations satisfy the Cartesian equation of a hyperbola.gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/parametric_eliminate, checked 2026-10-17 with SymPy 1.14.0.