Home›Calculus 2›Converting between polar and rectangular coordinates›Problem 8.216

Converting between polar and rectangular coordinates

Problem 8.216 · easy

Convert the rectangular point \( \displaystyle \left(\frac{3 \sqrt{2}}{2}, \frac{3 \sqrt{2}}{2}\right) \) to polar coordinates with \( \displaystyle r > 0 \) and \( \displaystyle 0 \le \theta < 2\pi \).

\[ 3 \]
r = √(x² + y²).✓ Proved
The point is in quadrant 1; θ = pi/4.
Reviewed
\[ \left[\begin{matrix}\frac{3 \sqrt{2}}{2}\\\frac{3 \sqrt{2}}{2}\end{matrix}\right] \]
Converting back gives the point.✓ Proved

Answer \( \left(3, \frac{\pi}{4}\right) \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt

Line	Status	Checked by	Detail
1	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
2	Reviewed	reviewers: gpt-oss:20b, qwen3.6:27b-mlx	a sentence; read, not computed
3	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
answer, a second way	✓ Checked independently	sympy 1.14.0 + mpmath 1.3.0	r and θ from hypot and atan2

Reviewers

gpt-oss:20b: pass
qwen3.6:27b-mlx: pass — The solution correctly identifies the quadrant and angle, and the algebraic verification confirms the radius and coordinates.

Every verdict on record (4)

gpt-oss:20b: pass 2026-10-13
qwen3.6:27b-mlx: pass 2026-10-13 — The solution correctly identifies the quadrant and angle, and the algebraic verification confirms the radius and coordinates.
gpt-oss:20b: pass 2026-10-13
qwen3.6:27b-mlx: pass 2026-10-13 — The solution correctly identifies the quadrant and the angle, and the radius calculation is correct. The steps are logically sound and lead to the correct answer.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/polar_conversion, checked 2026-10-13 with SymPy 1.14.0.