∫Calc Practice

Tangent lines to parametric curves

Problem 8.15 · hard

Find the equation of the tangent line to \( \displaystyle x = \cos{\left(t \right)},\ y = \sin{\left(t \right)} \) at \( \displaystyle t = \frac{\pi}{3} \).
  1. dy/dx = (dy/dt)/(dx/dt).
  2. \[ \frac{d}{d t} \cos{\left(t \right)} = - \sin{\left(t \right)} \]
    dx/dt.✓ Proved
  3. \[ \frac{d}{d t} \sin{\left(t \right)} = \cos{\left(t \right)} \]
    dy/dt.✓ Proved
  4. \[ \frac{\left(-1\right) \sqrt{3}}{3} = - \frac{\sqrt{3}}{3} \]
    The slope at t = \frac{\pi}{3}.✓ Proved
  5. \[ \left[\begin{matrix}1 \cdot \frac{1}{2}\\\frac{\sqrt{3}}{2}\end{matrix}\right] = \left[\begin{matrix}\frac{1}{2}\\\frac{\sqrt{3}}{2}\end{matrix}\right] \]
    The point.✓ Proved
  6. \[ - \frac{\sqrt{3} \left(x - \frac{1}{2}\right)}{3} + \frac{\sqrt{3}}{2} = - \frac{\sqrt{3} x}{3} + \frac{2 \sqrt{3}}{3} \]
    Point-slope form.✓ Proved
Answer \( y = - \frac{\sqrt{3} x}{3} + \frac{2 \sqrt{3}}{3} \)

Lines: 5 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The explanation has not been reviewed yet.

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0a secant through nearby points of the curve has the same slope; the line passes through the point

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/parametric_tangent, checked 2026-09-26 with SymPy 1.14.0.