∫Calc Practice

Converting between polar and rectangular coordinates

Problem 8.117 · easy

Write the polar equation \( \displaystyle r = 8 \cos{\left(\theta \right)} \) in rectangular form.
  1. Use x = r cos θ, y = r sin θ, r² = x² + y²; multiply by r: r² = 2a·r cos θ.
  2. \[ r^{2} \sin^{2}{\left(\theta \right)} + r^{2} \cos^{2}{\left(\theta \right)} - 8 r \cos{\left(\theta \right)} \]
    Substituting back gives an equation equivalent to the polar one.✓ Proved
Answer \( x^{2} + y^{2} = 8 x \)

Lines: 1 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0points on the polar curve at four angles satisfy the rectangular equation

Reviewers

  • gpt-oss:20b: fail (style) — [domain objection, downgraded to style] The first sentence incorrectly states the polar equation as r² = 2a·r cosθ and introduces an undefined constant a. It should be r² = 8r cosθ. The subsequent equation is also not derived correctly from the given polar form.
  • qwen3.6:27b-mlx: fail (error) — The solution fails to explicitly substitute the rectangular identities (x = r cos θ, r² = x² + y²) into the equation r² = 8r cos θ to derive the final answer x² + y² = 8x. It only verifies that the polar equation is consistent with itself, omitting the actual conversion step.
Every verdict on record (4)
  • qwen3.6:27b-mlx: fail (error) 2026-10-05 — The solution fails to explicitly substitute the rectangular identities (x = r cos θ, r² = x² + y²) into the equation r² = 8r cos θ to derive the final answer x² + y² = 8x. It only verifies that the polar equation is consistent with itself, omitting the actual conversion step.
  • gpt-oss:20b: fail (style) 2026-10-05 — [domain objection, downgraded to style] The first sentence incorrectly states the polar equation as r² = 2a·r cosθ and introduces an undefined constant a. It should be r² = 8r cosθ. The subsequent equation is also not derived correctly from the given polar form.
  • qwen3.6:27b-mlx: fail (error) 2026-10-05 — The solution fails to perform the actual conversion to rectangular coordinates. It substitutes the polar equation into an identity but never replaces r and theta with x and y to derive the final answer x^2 + y^2 = 8x.
  • gpt-oss:20b: fail (error) 2026-10-05 — The first sentence incorrectly introduces a parameter 2a and claims r² = 2a·r cosθ, which does not follow from the given polar equation r = 8 cosθ. The correct step is r² = 8r cosθ, leading to x² + y² = 8x. The solution omits this and contains a misapplied formula.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/polar_conversion, checked 2026-10-05 with SymPy 1.14.0.