Summing a series by differentiating or integrating
Problem 7.624 · hard
Find the sum of \( \displaystyle \sum_{n=1}^{\infty} \left(- \frac{1}{3}\right)^{n} n \).
- Differentiate Σ xⁿ = 1/(1 − x) term by term and multiply by x: Σ n xⁿ = x/(1 − x)² for |x| < 1.Reviewed
- \[ \frac{d}{d x} \frac{1}{1 - x} = \frac{1}{\left(1 - x\right)^{2}} \]d/dx of 1/(1 − x).✓ Proved
- \[ \left. x \frac{d}{d x} 1 \frac{1}{1 - x} \right|_{\substack{ x=- \frac{1}{3} }} = - \frac{3}{16} \]Put x = -1/3.✓ Proved
- \[ \sum_{n=1}^{\infty} \left(- \frac{1}{3}\right)^{n} n = - \frac{3}{16} \]Summed directly, the series agrees.✓ Proved
Answer \( - \frac{3}{16} \)
Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the first 399 terms added in floating point |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the series as a derivative of a geometric series and applies the standard formula within the radius of convergence. The logic is sound and the result is correct.
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-17 — The solution correctly identifies the series as a derivative of a geometric series and applies the standard formula within the radius of convergence. The logic is sound and the result is correct.gpt-oss:20b: pass 2026-10-17qwen3.6:27b-mlx: inconclusive 2026-10-15 — reviewer response could not be parsed: { "verdict": "fail", "severity": "error", "notes": "The derivation in step 1 is incorrect. Differentiating the geometric series \\(\\sum_{n=0}^{\\infty} x^n = \\frac{1}{1-x}\\) yields \\(\\sum_{n=1}^{gpt-oss:20b: pass 2026-10-15qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly derives the closed form for the arithmetico-geometric series and verifies the result. The steps are logically sound and the final answer is correct.gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/series_sum_by_calculus, checked 2026-10-17 with SymPy 1.14.0.