∫Calc Practice

Limits using Taylor series

Problem 7.601 · medium

Use Taylor series to evaluate \( \displaystyle \lim_{x\to 0} \frac{\cos{\left(x \right)} - 1}{x \sin{\left(x \right)}} \).
  1. Near 0, 1 - cos(x) = -x**4/24 + x**2/2 + ⋯ (its Maclaurin series).
  2. \[ \lim_{x \to 0}\left(\frac{\frac{x^{4}}{24} - \frac{x^{2}}{2} - \cos{\left(x \right)} + 1}{x^{4}}\right) = 0 \]
    The polynomial matches the numerator to that order.✓ Proved
  3. \[ \lim_{x \to 0}\left(\frac{\cos{\left(x \right)} - 1}{x \sin{\left(x \right)}}\right) = - \frac{1}{2} \]
    Let x → 0: only the constant term survives.✓ Proved
Answer \( - \frac{1}{2} \)

Lines: 2 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify

The full receipt
LineStatusChecked byDetail
1Not checked—a sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the expression at x = ±10⁻⁸ in 50-digit arithmetic

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (error) — The solution claims the limit is -1/2, but the correct value is -1/2. Wait, let me re-evaluate. cos(x) ~ 1 - x^2/2. sin(x) ~ x. Numerator ~ -x^2/2. Denominator ~ x^2. Ratio ~ -1/2. The answer is correct. However, the reasoning in line 3 is flawed. It says 'only the constant term survives' which is vague and potentially misleading if not explained properly (dividing series). But more importantly, line 1 states '1 - cos(x) = -x**4/24 + x**2/2 + ...'. This is correct. Line 2 checks the error term. Line 3 jumps to the answer. The logic is: (cos(x)-1)/(x sin(x)) = -(1-cos(x))/(x sin(x)). 1-cos(x) = x^2/2 - x^4/24 + ... x sin(x) = x(x - x^3/6 + ...) = x^2 - x^4/6 + ... Ratio = -(x^2/2 - ...)/(x^2 - ...) = -1/2. The solution skips the division step and just asserts the result. Is it an error? The sentence 'Let x -> 0: only the constant term survives' is a poor explanation of dividing power series. It implies substituting x=0 into the series terms directly, which would give 0/0. It fails to explain that one must divide the leading terms. This is misleading.
Every verdict on record (6)
  • qwen3.6:27b-mlx: fail (error) 2026-10-17 — The solution claims the limit is -1/2, but the correct value is -1/2. Wait, let me re-evaluate. cos(x) ~ 1 - x^2/2. sin(x) ~ x. Numerator ~ -x^2/2. Denominator ~ x^2. Ratio ~ -1/2. The answer is correct. However, the reasoning in line 3 is flawed. It says 'only the constant term survives' which is vague and potentially misleading if not explained properly (dividing series). But more importantly, line 1 states '1 - cos(x) = -x**4/24 + x**2/2 + ...'. This is correct. Line 2 checks the error term. Line 3 jumps to the answer. The logic is: (cos(x)-1)/(x sin(x)) = -(1-cos(x))/(x sin(x)). 1-cos(x) = x^2/2 - x^4/24 + ... x sin(x) = x(x - x^3/6 + ...) = x^2 - x^4/6 + ... Ratio = -(x^2/2 - ...)/(x^2 - ...) = -1/2. The solution skips the division step and just asserts the result. Is it an error? The sentence 'Let x -> 0: only the constant term survives' is a poor explanation of dividing power series. It implies substituting x=0 into the series terms directly, which would give 0/0. It fails to explain that one must divide the leading terms. This is misleading.
  • gpt-oss:20b: pass 2026-10-17
  • qwen3.6:27b-mlx: fail (error) 2026-10-15 — The solution incorrectly states the Maclaurin series for 1 - cos(x) as starting with x^2/2, but then uses a limit involving division by x^4 to justify the approximation, which is inconsistent and logically flawed for evaluating the given limit. The limit in line 2 is irrelevant to the problem statement and the conclusion in line 3 does not follow from the provided premises.
  • gpt-oss:20b: pass 2026-10-15
  • qwen3.6:27b-mlx: fail (error) 2026-10-14 — The solution incorrectly expands the numerator as 1 - cos(x) instead of the required cos(x) - 1, introducing a sign error. Additionally, the intermediate limit in step 2 is irrelevant to the problem statement and does not logically lead to the final result.
  • gpt-oss:20b: pass 2026-10-14

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/taylor_limit, checked 2026-10-17 with SymPy 1.14.0.