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Limits of sequences

Problem 7.505 · easy

Write the first four terms of \( \displaystyle a_n = \frac{2 n + 5}{5 n^{2} + 1} \), and determine whether the sequence converges. If it does, find its limit.
  1. \[ \left[\begin{matrix}\frac{7}{6}\\\frac{3}{7}\\\frac{11}{46}\\\frac{13}{81}\end{matrix}\right] \]
    The first four terms.✓ Proved
  2. The denominator has the higher degree.
    Reviewed
  3. \[ \lim_{n \to \infty}\left(\frac{2 n + 5}{5 n^{2} + 1}\right) = 0 \]
    The limit.✓ Proved
Answer \( a_1, \dots, a_4 = \frac{7}{6}, \frac{3}{7}, \frac{11}{46}, \frac{13}{81};\ 0 \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the terms evaluated at n = 10⁶, 10⁶ + 1 and 10⁷

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the first four terms and the limit. The reasoning that the limit is 0 because the denominator has a higher degree is standard and correct for rational functions.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-11 — The solution correctly identifies the first four terms and the limit. The reasoning that the limit is 0 because the denominator has a higher degree is standard and correct for rational functions.
  • gpt-oss:20b: pass 2026-10-11
  • qwen3.6:27b-mlx: pass 2026-10-11 — The solution correctly calculates the first four terms and identifies the limit as 0 based on the degree of the denominator being higher than the numerator. The reasoning is sound and concise.
  • gpt-oss:20b: pass 2026-10-11

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/sequence_limits, checked 2026-10-11 with SymPy 1.14.0.