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Telescoping series

Problem 7.395 · easy

Find the sum of \( \displaystyle \sum_{n=1}^{\infty} \frac{4}{n^{2} + 9 n + 18} \), or show that it diverges.
  1. \[ \frac{4}{n^{2} + 9 n + 18} = - \frac{4}{3 n + 18} + \frac{4}{3 n + 9} \]
    Partial fractions: the term is a difference.✓ Proved
  2. In the N-th partial sum every negative piece cancels a positive piece 3 terms later; only the first positive and last negative pieces survive.
    Reviewed
  3. So S_N = 37/45 - 4/(3*(N + 6)) - 4/(3*(N + 5)) - 4/(3*(N + 4)).
    Reviewed
  4. \[ \lim_{k \to \infty}\left(\frac{37}{45} - \frac{4}{3 k + 18} - \frac{4}{3 k + 15} - \frac{4}{3 k + 12}\right) = \frac{37}{45} \]
    Let N → ∞.✓ Proved
Answer \( \frac{37}{45} \)

✓ Nihil obstat Lines: 2 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
3Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0mpmath's nsum of the series (with convergence acceleration)

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the telescoping nature of the series with a shift of 3, accurately calculates the surviving terms for the partial sum, and correctly evaluates the limit.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly identifies the telescoping nature of the series with a shift of 3, accurately calculates the surviving terms for the partial sum, and correctly evaluates the limit.
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: pass 2026-10-07 — The solution correctly identifies the telescoping nature of the series with a shift of 3. The partial sum formula and the final limit are correct.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/telescoping_series, checked 2026-10-07 with SymPy 1.14.0.