∫Calc Practice

Power series from the geometric series

Problem 7.367 · medium

Find a power series for \( \displaystyle f(x) = \frac{3}{4 x^{2} + 1} \) centered at 0, and its interval of convergence.
  1. \[ \frac{3}{4 x^{2} + 1} \]
    Write f in the form (something)/(1 − u) with u = -4*x**2.✓ Proved
  2. 1/(1 − u) = Σ uⁿ for |u| < 1; substitute and multiply through.
    Reviewed
  3. \[ \lim_{x \to 0^+}\left(\frac{192 x^{6} - 48 x^{4} + 12 x^{2} - 3 + \frac{3}{4 x^{2} + 1}}{x^{6}}\right) = 0 \]
    The first terms -192*x**6 + 48*x**4 - 12*x**2 + 3 agree with f to order x^6.✓ Proved
  4. |u| < 1 means |x| < 1/2; the series diverges at both endpoints (the terms do not shrink).
    Reviewed
Answer \( \sum_{n=0}^{\infty} 3 \left(- 4 x^{2}\right)^{n},\quad |x| < \frac{1}{2} \)

Lines: 2 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the series summed numerically at half the radius matches f

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the geometric series form, applies the convergence condition for the geometric series, and correctly determines the interval of convergence.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: pass 2026-10-06 — The solution correctly identifies the geometric series form, applies the convergence condition for the geometric series, and correctly determines the interval of convergence.
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: fail (error) 2026-10-06 — The stated answer is mathematically incorrect; the coefficient of the series should be 3(-1)^n 4^n, not 3(-4x^2)^n which implies a variable coefficient. Additionally, the divergence at endpoints is not rigorously justified by 'terms do not shrink' without checking the specific limit of the terms.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/power_series_geometric, checked 2026-10-06 with SymPy 1.14.0.