Series convergence tests
Problem 7.30 · easy
Does \( \displaystyle \sum_{n=1}^{\infty} \frac{4 n + 1}{n^{3} + n + 1} \) converge or diverge?
- For large n the terms behave like 4/n^2: compare with the p-series Σ 1/n^2.
- \[ \lim_{n \to \infty}\left(\frac{n^{2} \left(4 n + 1\right)}{n^{3} + n + 1}\right) = 4 \]The limit is 4, positive and finite.✓ Proved
- Σ 1/n^2 converges (p = 2), so the given series does too.
Answer \( \text{converges} \)
Lines: 1 proved, 2 not checked. The answer was also checked a second way, without looking at the solution. The explanation has not been reviewed yet.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | Not checked | — | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | SymPy's own convergence decision (Sum.is_convergent) agrees |
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/series_convergence, checked 2026-09-26 with SymPy 1.14.0.