∫Calc Practice

Taylor and Maclaurin polynomials

Problem 7.138 · hard

Find the Maclaurin polynomial of degree 3 for \( \displaystyle f(x) = e^{x} \).
  1. p_n(x) = Σ f⁽ᵏ⁾(0)/k! · xᵏ, for k = 0 to n.
    Reviewed
  2. \[ \left. e^{x} \right|_{\substack{ x=0 }} = 1 \]
    f⁽0⁾(0).✓ Proved
  3. \[ \left. \frac{d}{d x} e^{x} \right|_{\substack{ x=0 }} = 1 \]
    f⁽1⁾(0).✓ Proved
  4. \[ \left. \frac{d^{2}}{d x^{2}} e^{x} \right|_{\substack{ x=0 }} = 1 \]
    f⁽2⁾(0).✓ Proved
  5. \[ \left. \frac{d^{3}}{d x^{3}} e^{x} \right|_{\substack{ x=0 }} = 1 \]
    f⁽3⁾(0).✓ Proved
  6. \[ x^{3} \cdot 1 \cdot \frac{1}{6} + x^{2} \cdot 1 \cdot \frac{1}{2} + x 1 + 1 = \frac{x^{3}}{6} + \frac{x^{2}}{2} + x + 1 \]
    Assemble the polynomial.✓ Proved
Answer \( p_{3}(x) = \frac{x^{3}}{6} + \frac{x^{2}}{2} + x + 1 \)

✓ Nihil obstat Lines: 5 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0sympy.series expands f on its own and matches

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-26
  • gpt-oss:20b: pass 2026-09-26
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly applies the definition of the Maclaurin polynomial, computes the necessary derivatives and their values at zero, and assembles the final polynomial accurately.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/taylor_polynomial, checked 2026-09-26 with SymPy 1.14.0.