Mixing tank problems
Problem 6.708 · medium
A tank holds \( \displaystyle 500 \) L of water with \( \displaystyle 100 \) kg of salt dissolved. Brine with 1/10 kg of salt per liter flows in at \( \displaystyle 5 \) L/min, and the well-mixed solution drains at the same rate. Find the salt \( \displaystyle S(t) \) in kg after \( \displaystyle t \) minutes, the amount after \( \displaystyle 60 \) minutes, and the long-run amount.
- Rate in − rate out: S′ = 5·1/10 − (5/500)S. The volume stays 500 L.Reviewed
- \[ \frac{d}{d t} \left(50 + 50 e^{- \frac{t}{100}}\right) = - \frac{e^{- \frac{t}{100}}}{2} \]This S(t) satisfies the equation ...✓ Proved
- \[ \left. 50 e^{\frac{\left(-1\right) t}{100}} + 50 \right|_{\substack{ t=0 }} = 100 \]... and starts at the given amount.✓ Proved
- \[ \left. 50 e^{\frac{\left(-1\right) t}{100}} + 50 \right|_{\substack{ t=60 }} = \frac{50}{e^{\frac{3}{5}}} + 50 \]S(60).✓ Proved
- \[ \lim_{t \to \infty}\left(50 + 50 e^{- \frac{t}{100}}\right) = 50 \]In the long run the tank matches the incoming concentration.✓ Proved
Answer \( S(t) = 50 + 50 e^{- \frac{t}{100}},\ S(60) = \frac{50}{e^{\frac{3}{5}}} + 50 \approx 77.441,\ \lim S = 50 \)
✓ Nihil obstat Lines: 4 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | mpmath's ODE solver integrates the tank from t = 0 |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-19gpt-oss:20b: pass 2026-10-19qwen3.6:27b-mlx: pass 2026-10-18 — The setup correctly models the mixing problem with the right rate in, rate out, and initial conditions. The solution satisfies the differential equation and boundary conditions as verified by the algebraic checks.gpt-oss:20b: pass 2026-10-18qwen3.6:27b-mlx: pass 2026-10-18gpt-oss:20b: pass 2026-10-18
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/mixing_tank, checked 2026-10-19 with SymPy 1.14.0.