Mixing tank problems
Problem 6.551 · medium
A tank holds \( \displaystyle 200 \) L of water with \( \displaystyle 10 \) kg of salt dissolved. Brine with 1/2 kg of salt per liter flows in at \( \displaystyle 4 \) L/min, and the well-mixed solution drains at the same rate. Find the salt \( \displaystyle S(t) \) in kg after \( \displaystyle t \) minutes, the amount after \( \displaystyle 30 \) minutes, and the long-run amount.
- Rate in − rate out: S′ = 4·1/2 − (4/200)S. The volume stays 200 L.Reviewed
- \[ \frac{d}{d t} \left(100 - 90 e^{- \frac{t}{50}}\right) = \frac{9 e^{- \frac{t}{50}}}{5} \]This S(t) satisfies the equation ...✓ Proved
- \[ \left. 100 - 90 e^{\frac{\left(-1\right) t}{50}} \right|_{\substack{ t=0 }} = 10 \]... and starts at the given amount.✓ Proved
- \[ \left. 100 - 90 e^{\frac{\left(-1\right) t}{50}} \right|_{\substack{ t=30 }} = 100 - \frac{90}{e^{\frac{3}{5}}} \]S(30).✓ Proved
- \[ \lim_{t \to \infty}\left(100 - 90 e^{- \frac{t}{50}}\right) = 100 \]In the long run the tank matches the incoming concentration.✓ Proved
Answer \( S(t) = 100 - 90 e^{- \frac{t}{50}},\ S(30) = 100 - \frac{90}{e^{\frac{3}{5}}} \approx 50.607,\ \lim S = 100 \)
✓ Nihil obstat Lines: 4 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | mpmath's ODE solver integrates the tank from t = 0 |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass
Every verdict on record (6)
qwen3.6:27b-mlx: pass 2026-10-18gpt-oss:20b: pass 2026-10-18qwen3.6:27b-mlx: pass 2026-10-16gpt-oss:20b: pass 2026-10-16qwen3.6:27b-mlx: pass 2026-10-14 — The setup correctly models the mixing problem with constant volume. The differential equation, solution, and subsequent evaluations are all correct.gpt-oss:20b: pass 2026-10-14
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/mixing_tank, checked 2026-10-18 with SymPy 1.14.0.