∫Calc Practice

Undetermined coefficients

Problem 6.284 · hard

Solve \( \displaystyle y'' - 3y' + 2y = -2 \) with \( \displaystyle y(0) = 0 \), \( \displaystyle y'(0) = 3 \).
  1. \[ r^{2} - 3 r + 2 = \left(r - 2\right) \left(r - 1\right) \]
    The characteristic equation has roots 1 and 2.✓ Proved
  2. So y_h = C₁e^(1x) + C₂e^(2x). Guess y_p = A.
    Reviewed
  3. \[ - 3 \frac{d}{d x} \left(-1\right) + \frac{d^{2}}{d x^{2}} \left(-1\right) - 2 = -2 \]
    Matching coefficients gives y_p = -1; it satisfies the equation.✓ Proved
  4. \[ \left[\begin{matrix}\left. 2 e^{2 x} - e^{x} - 1 \right|_{\substack{ x=0 }}\\\left. \frac{d}{d x} \left(2 e^{2 x} - e^{x} - 1\right) \right|_{\substack{ x=0 }}\end{matrix}\right] = \left[\begin{matrix}0\\3\end{matrix}\right] \]
    The initial conditions fix C₁ = -1 and C₂ = 2.✓ Proved
Answer \( y = 2 e^{2 x} - e^{x} - 1 \)

Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0SymPy's dsolve with the same initial conditions agrees

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: pass 2026-10-07
  • gpt-oss:20b: pass 2026-10-07
  • qwen3.6:27b-mlx: fail (error) 2026-10-07 — The solution skips the derivation of the constants C1 and C2, jumping directly to the final answer in the verification step. It fails to show the system of equations derived from the initial conditions (C1 + C2 = 1 and C1 + 2C2 = 3) and how they are solved.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/undetermined_coefficients, checked 2026-10-07 with SymPy 1.14.0.