∫Calc Practice

Second-order linear equations

Problem 6.180 · medium

Solve \( \displaystyle y'' + 0y' - 1y = 0 \) with \( \displaystyle y(0) = 1,\ y'(0) = 3 \).
  1. Try y = e^(mx): the characteristic equation is m² + bm + c = 0.
    Reviewed
  2. \[ \left(m - 1\right) \left(m + 1\right) = m^{2} - 1 \]
    Roots: -1, 1.✓ Proved
  3. Two real roots give y = C₁e^(r₁x) + C₂e^(r₂x).
    Reviewed
  4. Use y(0) and y'(0) to find C₁ and C₂.
    Reviewed
  5. \[ - 3 \sinh{\left(x \right)} - \cosh{\left(x \right)} + \frac{d^{2}}{d x^{2}} \left(3 \sinh{\left(x \right)} + \cosh{\left(x \right)}\right) = 0 \]
    The solution satisfies the equation.✓ Proved
  6. \[ 1 \]
    y(0).✓ Proved
  7. \[ 3 \]
    y'(0).✓ Proved
Answer \( y = 3 \sinh{\left(x \right)} + \cosh{\left(x \right)} \)

✓ Nihil obstat Lines: 4 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
7✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0sympy.checkodesol substitutes the solution back; both initial conditions match

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the characteristic equation, roots, and general form. The verification steps confirm that the stated answer satisfies both the differential equation and the initial conditions.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly identifies the characteristic equation, roots, and general form. The verification steps confirm that the stated answer satisfies both the differential equation and the initial conditions.
  • gpt-oss:20b: pass 2026-09-29
  • qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly identifies the characteristic equation, finds the roots, and verifies that the stated answer satisfies the differential equation and initial conditions.
  • gpt-oss:20b: pass 2026-09-29

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/second_order_linear, checked 2026-09-29 with SymPy 1.14.0.