∫Calc Practice

First-order linear equations

Problem 6.178 · hard

Solve \( \displaystyle y' + 3y = 3 x \) with \( \displaystyle y(0) = -1 \).
  1. The equation is linear in standard form; the integrating factor is e^(∫3 dx) = e^(3x).
    Reviewed
  2. \[ \frac{d}{d x} Y{\left(x \right)} e^{3 x} = 3 Y{\left(x \right)} e^{3 x} + e^{3 x} \frac{d}{d x} Y{\left(x \right)} \]
    Multiplying by e^(ax) turns the left side into (e^(ax) y)'.✓ Proved
  3. \[ \int 3 x e^{3 x}\, dx = \frac{\left(3 x - 1\right) e^{3 x}}{3} \]
    Integrate the right side.✓ Proved
  4. Setting x = 0 and y = -1 fixes the constant of integration: C = -2/3.
    Reviewed
  5. \[ 3 x + \frac{d}{d x} \left(x - \frac{1}{3} - \frac{2 e^{- 3 x}}{3}\right) - 1 - 2 e^{- 3 x} = 3 x \]
    The solution satisfies the equation.✓ Proved
  6. \[ -1 \]
    And the initial condition.✓ Proved
Answer \( y = x - \frac{1}{3} - \frac{2 e^{- 3 x}}{3} \)

✓ Nihil obstat Lines: 4 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0sympy.checkodesol substitutes the solution back; y(0) matches

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the integrating factor, performs the integration, determines the constant of integration, and verifies the final result.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly identifies the integrating factor, performs the integration, determines the constant of integration, and verifies the final result.
  • gpt-oss:20b: pass 2026-09-29
  • qwen3.6:27b-mlx: pass 2026-09-29 — The solution correctly identifies the integrating factor, performs the integration, applies the initial condition to find the constant, and verifies the final result. The logic is sound and complete.
  • gpt-oss:20b: pass 2026-09-29

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/linear_first_order, checked 2026-09-29 with SymPy 1.14.0.