∫Calc Practice

First-order linear equations

Problem 6.129 · medium

Solve \( \displaystyle y' + 1y = 6 \) with \( \displaystyle y(0) = 3 \).
  1. The equation is linear in standard form; the integrating factor is e^(∫1 dx) = e^(1x).
    Reviewed
  2. \[ \frac{d}{d x} Y{\left(x \right)} e^{x} = Y{\left(x \right)} e^{x} + e^{x} \frac{d}{d x} Y{\left(x \right)} \]
    Multiplying by e^(ax) turns the left side into (e^(ax) y)'.✓ Proved
  3. \[ \int 6 e^{x}\, dx = 6 e^{x} \]
    Integrate the right side.✓ Proved
  4. Setting x = 0 and y = 3 fixes the constant of integration: C = -3.
    Reviewed
  5. \[ \frac{d}{d x} \left(6 - 3 e^{- x}\right) + 6 - 3 e^{- x} = 6 \]
    The solution satisfies the equation.✓ Proved
  6. \[ 3 \]
    And the initial condition.✓ Proved
Answer \( y = 6 - 3 e^{- x} \)

✓ Nihil obstat Lines: 4 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0sympy.checkodesol substitutes the solution back; y(0) matches

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-27
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly identifies the integrating factor, applies the method of integrating factors, and verifies the final result against both the differential equation and the initial condition.
  • gpt-oss:20b: pass 2026-09-27

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/linear_first_order, checked 2026-09-27 with SymPy 1.14.0.