∫Calc Practice

First-order linear equations

Problem 6.126 · hard

Solve \( \displaystyle y' + 2y = x \) with \( \displaystyle y(0) = 4 \).
  1. The equation is linear in standard form; the integrating factor is e^(∫2 dx) = e^(2x).
    Reviewed
  2. \[ \frac{d}{d x} Y{\left(x \right)} e^{2 x} = 2 Y{\left(x \right)} e^{2 x} + e^{2 x} \frac{d}{d x} Y{\left(x \right)} \]
    Multiplying by e^(ax) turns the left side into (e^(ax) y)'.✓ Proved
  3. \[ \int x e^{2 x}\, dx = \frac{\left(2 x - 1\right) e^{2 x}}{4} \]
    Integrate the right side.✓ Proved
  4. Setting x = 0 and y = 4 fixes the constant of integration: C = 17/4.
    Reviewed
  5. \[ x + \frac{d}{d x} \left(\frac{x}{2} - \frac{1}{4} + \frac{17 e^{- 2 x}}{4}\right) - \frac{1}{2} + \frac{17 e^{- 2 x}}{2} = x \]
    The solution satisfies the equation.✓ Proved
  6. \[ 4 \]
    And the initial condition.✓ Proved
Answer \( y = \frac{x}{2} - \frac{1}{4} + \frac{17 e^{- 2 x}}{4} \)

Lines: 4 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0sympy.checkodesol substitutes the solution back; y(0) matches

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the integrating factor, performs the integration, applies the initial condition to find the constant, and verifies the final result.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly identifies the integrating factor, performs the integration, applies the initial condition to find the constant, and verifies the final result.
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: fail (error) 2026-09-27 — The solution skips the crucial step of dividing by the integrating factor to isolate y(x). It jumps from the integrated form to the final answer without showing the division by e^(2x), which is the core mechanism of the integrating factor method. Additionally, line 5 is not a verification of the differential equation (it computes x + y' instead of y' + 2y), making the 'proof' invalid.
  • gpt-oss:20b: pass 2026-09-27

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/linear_first_order, checked 2026-09-27 with SymPy 1.14.0.