∫Calc Practice

First-order linear equations

Problem 6.104 · hard

Solve \( \displaystyle y' + 4y = 3 x \) with \( \displaystyle y(0) = -1 \).
  1. The equation is linear in standard form; the integrating factor is e^(∫4 dx) = e^(4x).
    Reviewed
  2. \[ \frac{d}{d x} Y{\left(x \right)} e^{4 x} = 4 Y{\left(x \right)} e^{4 x} + e^{4 x} \frac{d}{d x} Y{\left(x \right)} \]
    Multiplying by e^(ax) turns the left side into (e^(ax) y)'.✓ Proved
  3. \[ \int 3 x e^{4 x}\, dx = \frac{\left(12 x - 3\right) e^{4 x}}{16} \]
    Integrate the right side.✓ Proved
  4. Setting x = 0 and y = -1 fixes the constant of integration: C = -13/16.
    Reviewed
  5. \[ 3 x + \frac{d}{d x} \left(\frac{3 x}{4} - \frac{3}{16} - \frac{13 e^{- 4 x}}{16}\right) - \frac{3}{4} - \frac{13 e^{- 4 x}}{4} = 3 x \]
    The solution satisfies the equation.✓ Proved
  6. \[ -1 \]
    And the initial condition.✓ Proved
Answer \( y = \frac{3 x}{4} - \frac{3}{16} - \frac{13 e^{- 4 x}}{16} \)

✓ Nihil obstat Lines: 4 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0sympy.checkodesol substitutes the solution back; y(0) matches

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the integrating factor, performs the integration, applies the initial condition to find the constant, and verifies the result.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly identifies the integrating factor, performs the integration, applies the initial condition to find the constant, and verifies the result.
  • gpt-oss:20b: pass 2026-09-26
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly identifies the integrating factor, performs the integration, applies the initial condition, and verifies the result. All steps are logically sound and algebraically correct.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/linear_first_order, checked 2026-09-26 with SymPy 1.14.0.