∫Calc Practice

First-order linear equations

Problem 6.101 · medium Video

Solve \( \displaystyle y' + 3y = e^{- 3 x} \) with \( \displaystyle y(0) = -2 \).
  1. The equation is linear in standard form; the integrating factor is e^(∫3 dx) = e^(3x).
    Reviewed
  2. \[ \frac{d}{d x} Y{\left(x \right)} e^{3 x} = 3 Y{\left(x \right)} e^{3 x} + e^{3 x} \frac{d}{d x} Y{\left(x \right)} \]
    Multiplying by e^(ax) turns the left side into (e^(ax) y)'.✓ Proved
  3. \[ \int 1\, dx = x \]
    Integrate the right side.✓ Proved
  4. Setting x = 0 and y = -2 fixes the constant of integration: C = -2.
    Reviewed
  5. \[ \left(3 x - 6\right) e^{- 3 x} + \frac{d}{d x} \left(x - 2\right) e^{- 3 x} = e^{- 3 x} \]
    The solution satisfies the equation.✓ Proved
  6. \[ -2 \]
    And the initial condition.Reviewed
Answer \( y = \left(x - 2\right) e^{- 3 x} \)
The slope field of y' = -3y + e^(-3x): short segments showing the slope at each point. Several solution curves follow the field; the one through (0, -2) is highlighted, y = (x - 2)·e^(-3x).

✓ Nihil obstat Lines: 3 proved, 3 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
5✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
6Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxboth sides are the same expression: the line states a value, and the working that produced it is not on the line
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0sympy.checkodesol substitutes the solution back; y(0) matches

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the integrating factor, solves the differential equation, and verifies both the differential equation and the initial condition. The logic is sound.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-09-27 — The solution correctly identifies the integrating factor, solves the differential equation, and verifies both the differential equation and the initial condition. The logic is sound.
  • gpt-oss:20b: pass 2026-09-27
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly identifies the integrating factor, solves the differential equation, and verifies both the differential equation and the initial condition. The logic is sound and the steps are clear.
  • gpt-oss:20b: pass 2026-09-26
  • qwen3.6:27b-mlx: pass 2026-09-26 — The solution correctly identifies the integrating factor, solves the differential equation, and determines the constant of integration using the initial condition. The final verification steps confirm the result.
  • gpt-oss:20b: pass 2026-09-26

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/linear_first_order, checked 2026-10-13 with SymPy 1.14.0.