The theorem of Pappus
Problem 5.654 · medium
The rectangle \( \displaystyle 2 \le x \le 5 \), \( \displaystyle 0 \le y \le 1 \) is rotated about the \( \displaystyle y \)-axis. Use the theorem of Pappus to find the volume.
- Pappus: V = A · 2πd, where d is the distance from the centroid to the axis.
- \[ 3 \cdot 1 = 3 \]Area = width × height.✓ Proved
- The centroid is the center, at x = 7/2.
- \[ 2 \pi 7 \cdot \frac{1}{2} \cdot 3 = 21 \pi \]V = 2π·d·A.✓ Proved
Answer \( 21 \pi \)
Lines: 2 proved, 2 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Not checked | — | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | Not checked | — | a sentence; read, not computed |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the volume by disks or shells, numerically |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: inconclusive — reviewer returned a non-object
Every verdict on record (6)
qwen3.6:27b-mlx: inconclusive 2026-10-18 — reviewer returned a non-objectgpt-oss:20b: pass 2026-10-18qwen3.6:27b-mlx: pass 2026-10-16 — The solution correctly identifies the area and centroid of the rectangle, and applies Pappus's Second Theorem accurately to find the volume.gpt-oss:20b: pass 2026-10-16qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly identifies the area and centroid of the rectangle, and applies Pappus's Second Theorem accurately to find the volume.gpt-oss:20b: pass 2026-10-15
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/pappus, checked 2026-10-18 with SymPy 1.14.0.