∫Calc Practice

Volumes with known cross sections

Problem 5.255 · medium

The base of a solid is the region under \( \displaystyle y = \sqrt{x} \) for \( \displaystyle 0 \le x \le 16 \). Cross-sections perpendicular to the \( \displaystyle x \)-axis are squares. Find the volume of the solid.
  1. \[ \sqrt{x} \]
    At position x the base of the cross-section has length (top − bottom).✓ Proved
  2. \[ x \]
    Area of one cross-section: 1·(side)².✓ Proved
  3. \[ \int\limits_{0}^{16} x\, dx = 128 \]
    Volume = ∫ A(x) dx across the base.✓ Proved
Answer \( 128 \)

Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0numerical quadrature of the cross-sectional area

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: fail (error) — The solution incorrectly identifies the side length of the square cross-section as x instead of sqrt(x). Consequently, it integrates x instead of (sqrt(x))^2 = x, but the logic presented in the sentences is incoherent and does not justify the setup. Specifically, line 1 claims the base length is sqrt(x) but line 2 implies the area is x (which is correct for the area, but the derivation is missing the squaring step explicitly linked to the side length). More critically, the text says 'Area... 1*(side)^2' but the equation is 'x=x', which is a tautology, not a derivation of Area = x. The student needs to see that side = sqrt(x), so Area = (sqrt(x))^2 = x. The current sentences are logically disconnected from the equations.
Every verdict on record (4)
  • qwen3.6:27b-mlx: fail (error) 2026-10-05 — The solution incorrectly identifies the side length of the square cross-section as x instead of sqrt(x). Consequently, it integrates x instead of (sqrt(x))^2 = x, but the logic presented in the sentences is incoherent and does not justify the setup. Specifically, line 1 claims the base length is sqrt(x) but line 2 implies the area is x (which is correct for the area, but the derivation is missing the squaring step explicitly linked to the side length). More critically, the text says 'Area... 1*(side)^2' but the equation is 'x=x', which is a tautology, not a derivation of Area = x. The student needs to see that side = sqrt(x), so Area = (sqrt(x))^2 = x. The current sentences are logically disconnected from the equations.
  • gpt-oss:20b: pass 2026-10-05
  • qwen3.6:27b-mlx: fail (error) 2026-10-05 — The solution incorrectly identifies the side length of the square cross-sections as x instead of sqrt(x), leading to the wrong integrand. The area should be (sqrt(x))^2 = x, but the setup implies the side is x, which is dimensionally and geometrically incorrect for the given base.
  • gpt-oss:20b: fail (misleading) 2026-10-05 — The solution’s sentences incorrectly describe the geometry: it states "sqrt(x)=sqrt(x) – At position x the base of the cross‑section has length (top − bottom)" and "x=x – Area of one cross‑section: 1·(side)²" without properly explaining that the side of each square is √x. While the final integral happens to be correct, the misleading wording could confuse a student about how the side length is determined.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/volume_cross_sections, checked 2026-10-05 with SymPy 1.14.0.