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Mass from a density

Problem 5.238 · easy

A thin disk of radius 3 cm has density \( \displaystyle \rho(r) = 2 e^{- r} \) g/cm² at distance \( \displaystyle r \) from its center. Find its mass.
  1. A thin ring at radius r has area about 2πr·dr, so its mass is 2πr·ρ(r)·dr.
    Reviewed
  2. \[ \int\limits_{0}^{3} 4 \pi r e^{- r}\, dr = - \frac{16 \pi}{e^{3}} + 4 \pi \]
    Add up the rings.✓ Proved
Answer \( - \frac{16 \pi}{e^{3}} + 4 \pi \approx 10.064 \)

✓ Nihil obstat Lines: 1 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0numerical quadrature

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The setup correctly identifies the differential mass element for a disk with radial symmetry, and the integration limits and result are correct.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-04 — The setup correctly identifies the differential mass element for a disk with radial symmetry, and the integration limits and result are correct.
  • gpt-oss:20b: pass 2026-10-04
  • qwen3.6:27b-mlx: pass 2026-10-04 — The setup correctly models the mass of a disk with radial density using annular rings, and the integration limits and result are correct.
  • gpt-oss:20b: pass 2026-10-04

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/mass_density, checked 2026-10-04 with SymPy 1.14.0.