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Riemann sums: left, right and midpoint

Problem 4.854 · medium

Compute the right Riemann sum \( \displaystyle R_{6} \) for \( \displaystyle f(x) = x^{3} + 1 \) on \( \displaystyle [-1, 2] \).

\[ 1 \cdot \frac{1}{2} = \frac{1}{2} \]
Δx = (b − a)/n.✓ Proved
The right endpoints are x = -1/2, 0, 1/2, 1, 3/2, 2.
Reviewed
\[ \frac{\frac{7}{8} + 1 + \frac{9}{8} + 2 + \frac{35}{8} + 9}{2} = \frac{147}{16} \]
Δx times the sum of the function values there.✓ Proved
For comparison, the exact integral is 27/4 ≈ 6.7500.
Reviewed

Answer \( R_{6} = \frac{147}{16} \approx 9.1875 \)

✓ Nihil obstat Lines: 2 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt

Line	Status	Checked by	Detail
1	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
2	Reviewed	reviewers: gpt-oss:20b, qwen3.6:27b-mlx	a sentence; read, not computed
3	✓ Proved	sympy 1.14.0	simplify(lhs - rhs) reduced to 0
4	Reviewed	reviewers: gpt-oss:20b, qwen3.6:27b-mlx	a sentence; read, not computed
answer, a second way	✓ Checked independently	sympy 1.14.0 + mpmath 1.3.0	the sum recomputed in 30-digit floating point

Reviewers

gpt-oss:20b: pass
qwen3.6:27b-mlx: pass — The solution correctly calculates the step size, identifies the right endpoints, and computes the Riemann sum. The comparison with the exact integral is accurate.

Every verdict on record (4)

gpt-oss:20b: pass 2026-10-10
qwen3.6:27b-mlx: pass 2026-10-10 — The solution correctly calculates the step size, identifies the right endpoints, and computes the Riemann sum. The comparison with the exact integral is accurate.
qwen3.6:27b-mlx: pass 2026-10-10 — The solution correctly calculates the step size, identifies the right endpoints, computes the function values, and sums them to get the correct Riemann sum. The comparison with the exact integral is also correct.
gpt-oss:20b: pass 2026-10-10

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/riemann_sums, checked 2026-10-10 with SymPy 1.14.0.