∫Calc Practice

Integrals giving inverse trig functions

Problem 4.808 · medium

Evaluate \( \displaystyle \int_{-2}^{-2 + \frac{5 \sqrt{2}}{2}} \frac{2}{\sqrt{- x^{2} - 4 x + 21}}\, dx \).
  1. \[ - x^{2} - 4 x + 21 = 25 - \left(x + 2\right)^{2} \]
    Complete the square.✓ Proved
  2. With u = x + 2 and a = 5, this is c·∫ du/√(a² − u²)
  3. \[ \frac{d}{d x} 2 \operatorname{asin}{\left(\frac{x}{5} + \frac{2}{5} \right)} = \frac{2}{\sqrt{- x^{2} - 4 x + 21}} \]
    An antiderivative is 2*asin(x/5 + 2/5); differentiate to confirm.✓ Proved
  4. \[ \frac{\pi}{2} \]
    Evaluate between the limits.✓ Proved
Answer \( \frac{\pi}{2} \)

Lines: 3 proved, 1 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Not checked—a sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0numerical quadrature

Reviewers

  • gpt-oss:20b: fail (misleading) — The solution’s sentences omit key details: the constant factor in the transformed integral is not stated, and the evaluation of the definite integral is glossed over with a trivial equality. A student could be misled into thinking the steps are fully justified when they are not.
  • qwen3.6:27b-mlx: pass — The solution correctly completes the square, identifies the standard arcsine integral form, and verifies the antiderivative. The final evaluation is correct.
Every verdict on record (4)
  • gpt-oss:20b: fail (misleading) 2026-10-10 — The solution’s sentences omit key details: the constant factor in the transformed integral is not stated, and the evaluation of the definite integral is glossed over with a trivial equality. A student could be misled into thinking the steps are fully justified when they are not.
  • qwen3.6:27b-mlx: pass 2026-10-10 — The solution correctly completes the square, identifies the standard arcsine integral form, and verifies the antiderivative. The final evaluation is correct.
  • gpt-oss:20b: fail (error) 2026-10-10 — The solution’s second sentence incorrectly states the transformed integral as a generic c·∫du/√(a²−u²) without specifying the correct integrand 2/√(a²−u²) or showing the change of limits. Additionally, the final evaluation step merely repeats π/2 without demonstrating how the definite integral yields that value. These omissions mean the setup and conclusion are incomplete and potentially misleading.
  • qwen3.6:27b-mlx: pass 2026-10-10 — The solution correctly completes the square, identifies the standard arcsine integral form, and verifies the antiderivative. The final evaluation is correct.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/inverse_trig_integral, checked 2026-10-10 with SymPy 1.14.0.