Riemann sums: left, right and midpoint
Problem 4.703 · medium
Compute the midpoint Riemann sum \( \displaystyle M_{4} \) for \( \displaystyle f(x) = 12 - x^{2} \) on \( \displaystyle [0, 2] \).
- \[ 1 \cdot \frac{1}{2} = \frac{1}{2} \]Δx = (b − a)/n.✓ Proved
- The midpoint points are x = 1/4, 3/4, 5/4, 7/4.Reviewed
- \[ \frac{\frac{143}{16} + \frac{167}{16} + \frac{183}{16} + \frac{191}{16}}{2} = \frac{171}{8} \]Δx times the sum of the function values there.✓ Proved
- For comparison, the exact integral is 64/3 ≈ 21.3333.Reviewed
Answer \( M_{4} = \frac{171}{8} \approx 21.3750 \)
✓ Nihil obstat Lines: 2 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the sum recomputed in 30-digit floating point |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the step size, midpoints, and function evaluations. The final calculation is correct.
Every verdict on record (4)
gpt-oss:20b: pass 2026-10-08qwen3.6:27b-mlx: pass 2026-10-08 — The solution correctly identifies the step size, midpoints, and function evaluations. The final calculation is correct.qwen3.6:27b-mlx: pass 2026-10-08 — The solution correctly identifies the step size, midpoints, and function evaluations. The final calculation is accurate.gpt-oss:20b: pass 2026-10-08
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/riemann_sums, checked 2026-10-08 with SymPy 1.14.0.