∫Calc Practice

Riemann sums: left, right and midpoint

Problem 4.545 · medium

Compute the midpoint Riemann sum \( \displaystyle M_{6} \) for \( \displaystyle f(x) = 3 x^{2} + 11 \) on \( \displaystyle [0, 1] \).
  1. \[ 1 \cdot \frac{1}{6} = \frac{1}{6} \]
    Δx = (b − a)/n.✓ Proved
  2. The midpoint points are x = 1/12, 1/4, 5/12, 7/12, 3/4, 11/12.
    Reviewed
  3. \[ \frac{\frac{529}{48} + \frac{179}{16} + \frac{553}{48} + \frac{577}{48} + \frac{203}{16} + \frac{649}{48}}{6} = \frac{1727}{144} \]
    Δx times the sum of the function values there.✓ Proved
  4. For comparison, the exact integral is 12 ≈ 12.0000.
    Reviewed
Answer \( M_{6} = \frac{1727}{144} \approx 11.9931 \)

✓ Nihil obstat Lines: 2 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0the sum recomputed in 30-digit floating point

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the subinterval width, the midpoints, and the final sum. The comparison with the exact integral is accurate and helpful context.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: pass 2026-10-06 — The solution correctly identifies the subinterval width, the midpoints, and the final sum. The comparison with the exact integral is accurate and helpful context.
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: pass 2026-10-06 — The solution correctly identifies the subinterval width, the midpoints, and the resulting Riemann sum. The comparison with the exact integral is accurate.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/riemann_sums, checked 2026-10-06 with SymPy 1.14.0.