∫Calc Practice

Partial fraction decomposition

Problem 4.533 · medium

Find the partial fraction decomposition of \( \displaystyle \frac{x^{2} + 5 x - 13}{x^{3} + 4 x^{2} + x + 4} \).
  1. \[ \left(x + 4\right) \left(x^{2} + 1\right) \]
    Factor the denominator.✓ Proved
  2. Set up one term per factor (a repeated factor gets a term for each power; an irreducible quadratic gets Bx + C on top), clear denominators, and match coefficients.
    Reviewed
  3. \[ \frac{x^{2} + 5 x - 13}{x^{3} + 4 x^{2} + x + 4} = \frac{2 x - 3}{x^{2} + 1} - \frac{1}{x + 4} \]
    The decomposition; recombining it gives back the original fraction.✓ Proved
Answer \( \frac{2 x - 3}{x^{2} + 1} - \frac{1}{x + 4} \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
2Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0SymPy's own apart() gives the same decomposition

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the factors of the denominator and sets up the appropriate partial fraction form. The final decomposition is verified algebraically.
Every verdict on record (4)
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: pass 2026-10-06 — The solution correctly identifies the factors of the denominator and sets up the appropriate partial fraction form. The final decomposition is verified algebraically.
  • gpt-oss:20b: pass 2026-10-06
  • qwen3.6:27b-mlx: pass 2026-10-06 — The solution correctly identifies the factors of the denominator and the appropriate form for the partial fraction decomposition. The final result is verified by the equation check.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/partial_fraction_decomp, checked 2026-10-06 with SymPy 1.14.0.