Definite integrals by substitution
Problem 4.451 · medium
Evaluate \( \displaystyle \int_{1}^{e^{2}} \frac{4 \ln{\left(x \right)}^{4}}{x}\, dx \).
- Let u = log(x); then du = 1/x dx, which is in the integrand up to a constant.Reviewed
- \[ \left. \ln{\left(x \right)} \right|_{\substack{ x=1 }} = 0 \]The lower limit in u.✓ Proved
- \[ \left. \ln{\left(x \right)} \right|_{\substack{ x=e^{2} }} = 2 \]The upper limit in u.✓ Proved
- \[ \int\limits_{0}^{2} 4 u^{4}\, du = \frac{128}{5} \]Integrate in u between the new limits; no back-substitution needed.✓ Proved
Answer \( \frac{128}{5} \)
✓ Nihil obstat Lines: 3 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | numerical quadrature of the original integral |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies u-substitution with proper limit transformation and integration.
Every verdict on record (4)
qwen3.6:27b-mlx: pass 2026-10-05 — The solution correctly applies u-substitution with proper limit transformation and integration.gpt-oss:20b: pass 2026-10-05qwen3.6:27b-mlx: pass 2026-10-05 — The solution correctly applies u-substitution with proper limit transformation and integration.gpt-oss:20b: pass 2026-10-05
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/definite_substitution, checked 2026-10-05 with SymPy 1.14.0.