∫Calc Practice

Integrals of powers of sine and cosine

Problem 4.412 · medium

Evaluate \( \displaystyle \int \sin{\left(x \right)} \cos^{2}{\left(x \right)}\, dx \).
  1. The power of sine is odd: keep one sin x for du, write the rest as (1 − cos²x)^0, and let u = cos x (du = −sin x dx).
    Reviewed
  2. \[ \frac{d}{d u} \left(- \frac{u^{3}}{3}\right) = - u^{2} \]
    ∫ -u**2 du = -u**3/3.✓ Proved
  3. \[ \frac{d}{d x} \left(- \frac{\cos^{3}{\left(x \right)}}{3}\right) = \sin{\left(x \right)} \cos^{2}{\left(x \right)} \]
    Differentiating the answer returns the integrand.✓ Proved
Answer \( - \frac{\cos^{3}{\left(x \right)}}{3} + C \)

✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.

The full receipt
LineStatusChecked byDetail
1Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxa sentence; read, not computed
2✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
3✓ Provedsympy 1.14.0simplify(lhs - rhs) reduced to 0
answer, a second way✓ Checked independentlysympy 1.14.0 + mpmath 1.3.0difference quotients of the answer match the integrand

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly identifies the strategy for integrating powers of sine and cosine with an odd power of sine. The substitution and integration steps are algebraically correct, and the final answer is verified by differentiation.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-05 — The solution correctly identifies the strategy for integrating powers of sine and cosine with an odd power of sine. The substitution and integration steps are algebraically correct, and the final answer is verified by differentiation.
  • gpt-oss:20b: pass 2026-10-05
  • qwen3.6:27b-mlx: pass 2026-10-05 — The solution correctly identifies the standard technique for integrating odd powers of sine. The setup, substitution, and final verification are all mathematically sound and clearly explained.
  • gpt-oss:20b: pass 2026-10-05

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by generator:structured/trig_powers_integral, checked 2026-10-05 with SymPy 1.14.0.