Partial fraction decomposition
Problem 4.393 · medium
Find the partial fraction decomposition of \( \displaystyle \frac{6 x - 4}{\left(x - 3\right) \left(x + 4\right)} \).
- \[ \left(x + 4\right) \left(x - 3\right) = \left(x - 3\right) \left(x + 4\right) \]Factor the denominator.✓ Proved
- Set up one term per factor (a repeated factor gets a term for each power; an irreducible quadratic gets Bx + C on top), clear denominators, and match coefficients.Reviewed
- \[ \frac{6 x - 4}{\left(x - 3\right) \left(x + 4\right)} = \frac{4}{x + 4} + \frac{2}{x - 3} \]The decomposition; recombining it gives back the original fraction.✓ Proved
Answer \( \frac{4}{x + 4} + \frac{2}{x - 3} \)
✓ Nihil obstat Lines: 2 proved, 1 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | SymPy's own apart() gives the same decomposition |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the form of the partial fraction decomposition and provides the correct result, which is verified by the algebraic check.
Every verdict on record (4)
qwen3.6:27b-mlx: pass 2026-10-05 — The solution correctly identifies the form of the partial fraction decomposition and provides the correct result, which is verified by the algebraic check.gpt-oss:20b: pass 2026-10-05qwen3.6:27b-mlx: pass 2026-10-05 — The solution correctly identifies the form of the partial fraction decomposition and provides the correct coefficients. The setup sentence accurately describes the standard method for distinct linear factors.gpt-oss:20b: pass 2026-10-05
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/partial_fraction_decomp, checked 2026-10-05 with SymPy 1.14.0.