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Integral of \( \displaystyle \frac{1}{3 x \left(3 x + 1\right)^{2}} \)

Problem 4.368 · medium

Find \( \displaystyle \int \frac{1}{3 x \left(3 x + 1\right)^{2}} \, dx \). (Omit the constant of integration.)
  1. \[ \int \frac{1}{3 x \left(3 x + 1\right)^{2}}\, dx \]
    integralStart with the integral of the given function.✓ Proved
  2. \[ = \int \left(- \frac{1}{3 x + 1} - \frac{1}{\left(3 x + 1\right)^{2}} + \frac{1}{3 x}\right)\, dx \]
    rewriteDecompose the integrand using partial fraction decomposition.✓ Proved
  3. \[ = \int \frac{1}{3 x}\, dx - \int \frac{1}{\left(3 x + 1\right)^{2}}\, dx - \int \frac{1}{3 x + 1}\, dx \]
    linearityDistribute the integral across the terms.≈ Checked numerically
  4. \[ = \frac{\ln{\left(x \right)}}{3} - \int \frac{1}{\left(3 x + 1\right)^{2}}\, dx - \int \frac{1}{3 x + 1}\, dx \]
    antiderivativeIntegrate the first term.✓ Proved
  5. \[ = \frac{\ln{\left(x \right)}}{3} - \frac{\ln{\left(3 x + 1 \right)}}{3} - \int \frac{1}{\left(3 x + 1\right)^{2}}\, dx \]
    antiderivativeIntegrate the second term.✓ Proved
  6. \[ = \frac{\ln{\left(x \right)}}{3} - \frac{\ln{\left(3 x + 1 \right)}}{3} + \frac{1}{9 x + 3} \]
    antiderivativeIntegrate the final term using the power rule.✓ Proved
Answer \( \frac{\ln{\left(x \right)}}{3} - \frac{\ln{\left(x + \frac{1}{3} \right)}}{3} + \frac{1}{9 x + 3} + C \)

Lines: 5 proved, 2 checked numerically. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
undefined where 3*x + 1 = 0
3≈ Checked numericallysympy 1.14.0sympy 1.14.0: simplify left -log(x + 1/3)/3 + log(3*x + 1)/3; numeric agreement only, at 24 of 24 sampled points
undefined where x = 0
undefined where 3*x + 1 = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x = 0
undefined where 3*x + 1 = 0
log is undefined for non-positive arguments
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 3*x + 1 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
log is undefined for non-positive arguments
undefined where 3*x + 1 = 0
undefined where 9*x + 3 = 0
answer≈ Checked numericallysympy 1.14.0sympy 1.14.0: final line against the stated answer: simplify left log(x + 1/3)/3 - log(3*x + 1)/3; numeric agreement only, at 24 of 24 sampled points
log is undefined for non-positive arguments
undefined where 9*x + 3 = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated the stated antiderivative back to the integrand

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-05
  • gpt-oss:20b: pass 2026-10-05
  • qwen3.6:27b-mlx: pass 2026-10-05 — The solution correctly applies partial fraction decomposition, linearity, and antiderivative rules in separate steps. The final answer is algebraically equivalent to the stated answer.
  • gpt-oss:20b: fail (error) 2026-10-05 — Step 6 applies the antiderivative of (3x+1)^{-2} incorrectly: ∫(3x+1)^{-2}dx = -(1/3)(3x+1)^{-1}, not +(1/3)(3x+1)^{-1}. The sign of the final term is wrong.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-05 with SymPy 1.14.0.