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Integral of \( \displaystyle \frac{\sin{\left(x + 1 \right)}}{\cos^{2}{\left(x + 1 \right)}} \)

Problem 4.280 · medium

Find \( \displaystyle \int \frac{\sin{\left(x + 1 \right)}}{\cos^{2}{\left(x + 1 \right)}} \, dx \). (Omit the constant of integration.)
  1. \[ \int \frac{\sin{\left(x + 1 \right)}}{\cos^{2}{\left(x + 1 \right)}}\, dx \]
    integral algebraStart with the integral of the given function. Rewrite the denominator using a negative exponent.✓ Proved
  2. \[ = \int \frac{\tan{\left(x + 1 \right)}}{\cos{\left(x + 1 \right)}}\, dx \]
    trig-identityUse the identity sin(u)/cos(u) = tan(u).Reviewed
  3. \[ = \int \tan{\left(x + 1 \right)} \sec{\left(x + 1 \right)}\, dx \]
    trig-identityUse the identity 1/cos(u) = sec(u).Reviewed
  4. \[ = \sec{\left(x + 1 \right)} \]
    antiderivativeThe antiderivative of tan(u)sec(u) is sec(u).✓ Proved
Answer \( \frac{1}{\cos{\left(x + 1 \right)}} + C \)

Lines: 4 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt.

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where cos(x + 1) = 0
3Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxsimplify left -Integral(tan(x + 1)/cos(x + 1), x) + 1/cos(x + 1); no point in the sample was defined on both lines
undefined where cos(x + 1) = 0
tan has poles at odd multiples of pi/2
4Reviewedreviewers: gpt-oss:20b, qwen3.6:27b-mlxsimplify left -sec(x + 1) + Integral(tan(x + 1)/cos(x + 1), x); no point in the sample was defined on both lines
tan has poles at odd multiples of pi/2
undefined where cos(x + 1) = 0
sec has poles at odd multiples of pi/2
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
undefined where cos(x + 1) = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated the stated antiderivative back to the integrand

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies trigonometric identities to rewrite the integrand as tan(x+1)sec(x+1) and then identifies the antiderivative. Each step applies a single rule from the allowed vocabulary.
Every verdict on record (4)
  • qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly applies trigonometric identities to rewrite the integrand as tan(x+1)sec(x+1) and then identifies the antiderivative. Each step applies a single rule from the allowed vocabulary.
  • gpt-oss:20b: pass 2026-10-04
  • qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly applies algebraic rewriting and trigonometric identities to transform the integrand into a standard form, then applies the known antiderivative rule. Each step changes only one aspect of the expression and uses valid labels from the vocabulary.
  • gpt-oss:20b: fail (error) 2026-10-04 — Step 3 applies two transformations at once: it replaces sin(x+1)/cos(x+1)^2 with tan(x+1)*sec(x+1), using both sin/cos = tan and 1/cos = sec. This violates the rule that each step must change only one thing and be labeled with a single rule.

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-04 with SymPy 1.14.0.