Integral of \( \displaystyle \frac{2 x - 1}{2 x \left(2 x + 2\right)} \)
Problem 4.276 · medium
Find \( \displaystyle \int \frac{2 x - 1}{2 x \left(2 x + 2\right)} \, dx \). (Omit the constant of integration.)
- \[ \int \frac{2 x - 1}{2 x \left(2 x + 2\right)}\, dx \]integralStart with the integral of the given function.✓ Proved
- \[ = \int \frac{2 x - 1}{4 x^{2} + 4 x}\, dx \]algebraExpand the denominator.✓ Proved
- \[ = \int \left(\frac{2 x}{4 x^{2} + 4 x} - \frac{1}{4 x^{2} + 4 x}\right)\, dx \]linearitySplit the integrand into two parts.✓ Proved
- \[ = \int \left(- \frac{1}{4 x^{2} + 4 x} + \frac{1}{2 x + 2}\right)\, dx \]simplifySimplify the first term by canceling x.✓ Proved
- \[ = \int \frac{1}{2 x + 2}\, dx - \int \frac{1}{4 x^{2} + 4 x}\, dx \]linearitySplit the integral again.✓ Proved
- \[ = - \int \frac{1}{4 x \left(x + 1\right)}\, dx + \int \frac{1}{2 x + 2}\, dx \]algebraFactor out the constant from the second denominator.✓ Proved
- \[ = \int \frac{1}{2 x + 2}\, dx - \int \frac{1}{4 x^{2} + 4 x}\, dx \]algebraFactor out 4 from the second term.✓ Proved
- \[ = - \frac{\int \frac{1}{x \left(x + 1\right)}\, dx}{4} + \int \frac{1}{2 x + 2}\, dx \]linearityPull out the constant factor.✓ Proved
- \[ = \int \frac{1}{2 x + 2}\, dx - \frac{\int \left(- \frac{1}{x + 1} + \frac{1}{x}\right)\, dx}{4} \]partial-fractionsApply partial fraction decomposition to the second term.✓ Proved
- \[ = - \frac{\int \frac{1}{x}\, dx}{4} + \frac{\int \frac{1}{x + 1}\, dx}{4} + \int \frac{1}{2 x + 2}\, dx \]linearityDistribute the constant and split the integral.✓ Proved
- \[ = - \frac{\ln{\left(x \right)}}{4} + \frac{\ln{\left(x + 1 \right)}}{4} + \frac{\ln{\left(2 x + 2 \right)}}{2} \]antiderivativeEvaluate the integrals using the natural logarithm rule.✓ Proved
Answer \( \frac{- \ln{\left(x \right)} + 3 \ln{\left(x + 1 \right)}}{4} + C \)
✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 2*x + 2 = 0 undefined where x = 0 undefined where 4*x**2 + 4*x = 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 4*x**2 + 4*x = 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 4*x**2 + 4*x = 0 undefined where 2*x + 2 = 0 |
| 5 | ✓ Proved | sympy 1.14.0 | lines differ by the constant -log(2)/2 undefined where 2*x + 2 = 0 undefined where 4*x**2 + 4*x = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 4*x**2 + 4*x = 0 undefined where 2*x + 2 = 0 undefined where x + 1 = 0 undefined where x = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x + 1 = 0 undefined where 2*x + 2 = 0 undefined where x = 0 undefined where 4*x**2 + 4*x = 0 |
| 8 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where 4*x**2 + 4*x = 0 undefined where 2*x + 2 = 0 undefined where x + 1 = 0 undefined where x = 0 |
| 9 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x + 1 = 0 undefined where 2*x + 2 = 0 undefined where x = 0 |
| 10 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x + 1 = 0 undefined where 2*x + 2 = 0 undefined where x = 0 |
| 11 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 undefined where x + 1 = 0 undefined where 2*x + 2 = 0 undefined where x = 0 log is undefined for non-positive arguments |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: lines differ by the constant log(2)/2 log is undefined for non-positive arguments |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated the stated antiderivative back to the integrand |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly applies algebraic simplification, linearity, and partial fraction decomposition. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
Every verdict on record (4)
qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly applies algebraic simplification, linearity, and partial fraction decomposition. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.gpt-oss:20b: pass 2026-10-04qwen3.6:27b-mlx: pass 2026-10-04 — The solution correctly applies algebraic simplification, linearity, and partial fraction decomposition. Each step modifies only one aspect of the expression and uses valid labels from the fixed vocabulary.gpt-oss:20b: pass 2026-10-04
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-10-04 with SymPy 1.14.0.