Integral of \( \displaystyle \frac{\ln{\left(2 x + 1 \right)}}{2 x + 1} \)
Problem 4.1482 · medium Video
Find \( \displaystyle \int \frac{\ln{\left(2 x + 1 \right)}}{2 x + 1} \, dx \). (Omit the constant of integration.)
- \[ \int \frac{\ln{\left(2 x + 1 \right)}}{2 x + 1}\, dx \]integral algebra algebra algebra simplify simplifyStart with the integral of the given function. Rewrite the fraction using a negative exponent. Multiply by 1 in the form of 2/2. Rearrange the terms. Simplify the expression. Simplify the constant factor.✓ Proved
- \[ = 0.25 \ln{\left(2 x + 1 \right)}^{2} \]antiderivativeApply the power rule for integration via substitution u = log(2x+1).✓ Proved
Answer \( \frac{\ln{\left(2 x + 1 \right)}^{2}}{4} + C \)
Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | line 1 is the problem as stated |
| 2 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x + 1 = 0 |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x + 1 = 0 |
| 4 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x + 1 = 0 |
| 5 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x + 1 = 0 |
| 6 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x + 1 = 0 |
| 7 | ✓ Proved | sympy 1.14.0 | simplify(a - b) reduced to 0 log is undefined for non-positive arguments undefined where 2*x + 1 = 0 |
| answer | ✓ Proved | sympy 1.14.0 | final line against the stated answer: simplify(a - b) reduced to 0 log is undefined for non-positive arguments |
| answer, a second way | ✓ Proved | sympy 1.14.0 | SymPy differentiated the stated antiderivative back to the integrand |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: fail (error) — Steps 3 through 6 perform redundant algebraic manipulations (multiplying by 1 and rearranging) that do not constitute a single valid rule application in the context of solving the integral, effectively stalling the solution. More critically, Step 7 jumps directly to the final answer without showing the substitution step required by the 'substitution' rule, violating the one-step constraint.
Every verdict on record (6)
qwen3.6:27b-mlx: fail (error) 2026-11-10 — Steps 3 through 6 perform redundant algebraic manipulations (multiplying by 1 and rearranging) that do not constitute a single valid rule application in the context of solving the integral, effectively stalling the solution. More critically, Step 7 jumps directly to the final answer without showing the substitution step required by the 'substitution' rule, violating the one-step constraint.gpt-oss:20b: pass 2026-11-10qwen3.6:27b-mlx: fail (style) 2026-11-09 — Steps 2 through 6 perform redundant algebraic manipulations (multiplying by 1 and rearranging) that do not advance the solution, violating the principle that each step should change one thing meaningfully. Step 7 jumps from the integral to the final answer without showing the substitution step, applying multiple rules (substitution and integration) at once.gpt-oss:20b: fail (style) 2026-11-09 — Step 4 rearranges the integrand in a way that effectively applies two algebraic manipulations at once (pulling a factor of 2 out and dividing by 2), violating the rule that each step must change only one thing. The rest of the solution is correct.qwen3.6:27b-mlx: fail (style) 2026-11-09 — Steps 3 through 6 are redundant and do not change the mathematical expression, violating the requirement that each step changes one thing. Step 7 applies substitution and integration in a single step, which should be split into a substitution step and an antiderivative step.gpt-oss:20b: pass 2026-11-09
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
gemma4:26b, checked 2026-11-10 with SymPy 1.14.0.