Riemann sums: left, right and midpoint
Problem 4.1457 · medium Video
Compute the right Riemann sum \( \displaystyle R_{4} \) for \( \displaystyle f(x) = x^{2} - 3 x + 9 \) on \( \displaystyle [-1, 1] \).
- \[ \frac{1 + 1}{4} = \frac{1}{2} \]Δx = (b − a)/n.✓ Proved
- The right endpoints are x = -1/2, 0, 1/2, 1.
- \[ \frac{7 + \frac{31}{4} + 9 + \frac{43}{4}}{2} = \frac{69}{4} \]Δx times the sum of the function values there.✓ Proved
- For comparison, the exact integral is 56/3 ≈ 18.6667.
Answer \( R_{4} = \frac{69}{4} \approx 17.2500 \)
Lines: 2 proved, 2 not checked. The answer was also checked a second way, without looking at the solution. The reviewers disagree about how one step is explained; every verdict is in the receipt. How we verify
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | Not checked | — | a sentence; read, not computed |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | Not checked | — | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the sum recomputed in 30-digit floating point |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: inconclusive — reviewer returned a non-object
Every verdict on record (6)
qwen3.6:27b-mlx: inconclusive 2026-11-07 — reviewer returned a non-objectgpt-oss:20b: pass 2026-11-07qwen3.6:27b-mlx: inconclusive 2026-11-06 — reviewer returned a non-objectgpt-oss:20b: pass 2026-11-06qwen3.6:27b-mlx: pass 2026-11-06 — The solution correctly identifies the step size, right endpoints, and function values. The arithmetic is correct, and the comparison with the exact integral is accurate.gpt-oss:20b: pass 2026-11-06
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/riemann_sums, checked 2026-11-07 with SymPy 1.14.0.