∫Calc Practice

Integral of \( \displaystyle \left(3 x + 1\right)^{\frac{3}{2}} - \frac{1}{\sqrt{3 x + 1}} \)

Problem 4.1409 · hard Video

Find \( \displaystyle \int \left(3 x + 1\right)^{\frac{3}{2}} - \frac{1}{\sqrt{3 x + 1}} \, dx \). (Omit the constant of integration.)
  1. \[ \int \left(\left(3 x + 1\right)^{\frac{3}{2}} - \frac{1}{\sqrt{3 x + 1}}\right)\, dx \]
    integral rewriteStart with the integral of the given function. Rewrite the square root using a fractional exponent.✓ Proved
  2. \[ = - \int \frac{1}{\sqrt{3 x + 1}}\, dx + \int \left(3 x + 1\right)^{\frac{3}{2}}\, dx \]
    linearity algebraSplit the integral into two parts. Factor out the 3 from the base.✓ Proved
  3. \[ = - \int \frac{\sqrt{3}}{3 \sqrt{x + \frac{1}{3}}}\, dx + \int 3 \sqrt{3} \left(x + \frac{1}{3}\right)^{\frac{3}{2}}\, dx \]
    algebraDistribute the power to the factored terms.✓ Proved
  4. \[ = - \frac{\sqrt{3} \int \frac{1}{\sqrt{x + \frac{1}{3}}}\, dx}{3} + 3 \sqrt{3} \int \left(x + \frac{1}{3}\right)^{\frac{3}{2}}\, dx \]
    linearityPull the constant coefficients out of the integrals.✓ Proved
  5. \[ = \frac{6 \sqrt{3} \left(x + \frac{1}{3}\right)^{\frac{5}{2}}}{5} - \frac{2 \sqrt{3} \sqrt{x + \frac{1}{3}}}{3} \]
    antiderivative simplify rewriteApply the power rule for integration. Group the constants. Rewrite the term (x + 1/3) in terms of (3x + 1).✓ Proved
  6. \[ = \frac{2 \left(3 x + 1\right)^{\frac{5}{2}}}{15} - \frac{2 \sqrt{3 x + 1}}{3} \]
    algebra algebra algebra simplifyDistribute the exponent to the numerator and denominator. Combine the powers of 3. Simplify the exponents. Final simplification of the coefficients.✓ Proved
Answer \( \frac{2 \sqrt{3 x + 1} \left(\left(3 x + 1\right)^{2} - 5\right)}{15} + C \)
Top: the graph of F = 2sqrt(3x + 1)·((3x + 1)² - 5)/15. A tangent line slides along it, and its slope is plotted below as it goes, tracing f = (3x + 1)^(3/2) - 1/sqrt(3x + 1).

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 3*x + 1 = 0
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 3*x + 1 = 0
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 3*x + 1 = 0
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where 3*x + 1 = 0
undefined where x + 1/3 = 0
6✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x + 1/3 = 0
7✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where x + 1/3 = 0
8✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
9✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
10✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
11✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
12✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
13✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated the stated antiderivative back to the integrand

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass — The solution correctly applies the rules of integration, algebraic manipulation, and simplification. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-11-02 — The solution correctly applies the rules of integration, algebraic manipulation, and simplification. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-11-02
  • qwen3.6:27b-mlx: pass 2026-11-01 — The solution correctly applies the power rule for integration via substitution, handling the constant factors algebraically. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-11-01
  • qwen3.6:27b-mlx: pass 2026-11-01 — The solution correctly applies the power rule for integration via substitution, handling the constant factors algebraically in subsequent steps. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-11-01

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-11-02 with SymPy 1.14.0.