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Integral of \( \displaystyle \frac{\sin{\left(3 x \right)}}{\cos^{2}{\left(3 x \right)}} \)

Problem 4.1129 · medium Video

Find \( \displaystyle \int \frac{\sin{\left(3 x \right)}}{\cos^{2}{\left(3 x \right)}} \, dx \). (Omit the constant of integration.)
  1. \[ \int \frac{\sin{\left(3 x \right)}}{\cos^{2}{\left(3 x \right)}}\, dx \]
    integralStart with the integral of the given function.✓ Proved
  2. \[ = \int \frac{\tan{\left(3 x \right)}}{\cos{\left(3 x \right)}}\, dx \]
    rewriteRewrite the denominator as a power of cosine.✓ Proved
  3. \[ = \int \tan{\left(3 x \right)} \sec{\left(3 x \right)}\, dx \]
    rewrite simplifyUse the identity 1/cos(3*x) = sec(3*x). Simplify the integrand.✓ Proved
  4. \[ = \frac{\sec{\left(3 x \right)}}{3} \]
    antiderivativeApply the antiderivative rule for sec(ax)tan(ax).✓ Proved
Answer \( \frac{1}{3 \cos{\left(3 x \right)}} + C \)
Top: the graph of F = 1/(3cos(3x)). A tangent line slides along it, and its slope is plotted below as it goes, tracing f = sin(3x)/cos(3x)².

✓ Nihil obstat Every line of this solution was proved by the computer algebra system SymPy. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation. How we verify

The full receipt
LineStatusChecked byDetail
1✓ Provedsympy 1.14.0line 1 is the problem as stated
2✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
undefined where cos(3*x) = 0
tan has poles at odd multiples of pi/2
3✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
undefined where cos(3*x) = 0
sec has poles at odd multiples of pi/2
4✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
5✓ Provedsympy 1.14.0simplify(a - b) reduced to 0
tan has poles at odd multiples of pi/2
sec has poles at odd multiples of pi/2
answer✓ Provedsympy 1.14.0final line against the stated answer: simplify(a - b) reduced to 0
undefined where cos(3*x) = 0
answer, a second way✓ Provedsympy 1.14.0SymPy differentiated the stated antiderivative back to the integrand

Reviewers

  • gpt-oss:20b: pass
  • qwen3.6:27b-mlx: pass
Every verdict on record (6)
  • qwen3.6:27b-mlx: pass 2026-10-17
  • gpt-oss:20b: pass 2026-10-17
  • qwen3.6:27b-mlx: pass 2026-10-15 — The solution correctly applies trigonometric identities to transform the integrand into a standard form and then applies the antiderivative rule. Each step changes only one aspect of the expression and uses valid labels from the fixed vocabulary.
  • gpt-oss:20b: pass 2026-10-15
  • qwen3.6:27b-mlx: pass 2026-10-14 — The solution correctly applies substitution and standard antiderivative rules with appropriate labels. Each step changes only one aspect of the expression.
  • gpt-oss:20b: pass 2026-10-14

Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence, not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by gemma4:26b, checked 2026-10-17 with SymPy 1.14.0.