Riemann sums: left, right and midpoint
Problem 4.1006 · medium
Compute the midpoint Riemann sum \( \displaystyle M_{6} \) for \( \displaystyle f(x) = 12 - x^{2} \) on \( \displaystyle [-1, 2] \).
- \[ 1 \cdot \frac{1}{2} = \frac{1}{2} \]Δx = (b − a)/n.✓ Proved
- The midpoint points are x = -3/4, -1/4, 1/4, 3/4, 5/4, 7/4.Reviewed
- \[ \frac{\frac{143}{16} + \frac{167}{16} + \frac{183}{16} + \frac{183}{16} + \frac{191}{16} + \frac{191}{16}}{2} = \frac{529}{16} \]Δx times the sum of the function values there.✓ Proved
- For comparison, the exact integral is 33 ≈ 33.0000.Reviewed
Answer \( M_{6} = \frac{529}{16} \approx 33.0625 \)
✓ Nihil obstat Lines: 2 proved, 2 reviewed. The answer was also checked a second way, without looking at the solution. Reviewers found nothing wrong with the explanation.
The full receipt
| Line | Status | Checked by | Detail |
|---|---|---|---|
| 1 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 2 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| 3 | ✓ Proved | sympy 1.14.0 | simplify(lhs - rhs) reduced to 0 |
| 4 | Reviewed | reviewers: gpt-oss:20b, qwen3.6:27b-mlx | a sentence; read, not computed |
| answer, a second way | ✓ Checked independently | sympy 1.14.0 + mpmath 1.3.0 | the sum recomputed in 30-digit floating point |
Reviewers
gpt-oss:20b: passqwen3.6:27b-mlx: pass — The solution correctly identifies the subinterval width and midpoints, computes the Riemann sum accurately, and provides a correct comparison with the exact integral.
Every verdict on record (4)
gpt-oss:20b: pass 2026-10-13qwen3.6:27b-mlx: pass 2026-10-13 — The solution correctly identifies the subinterval width and midpoints, computes the Riemann sum accurately, and provides a correct comparison with the exact integral.gpt-oss:20b: pass 2026-10-13qwen3.6:27b-mlx: pass 2026-10-13 — The solution correctly identifies the subinterval width, the midpoints, and the resulting sum. The comparison with the exact integral is accurate.
Proved: SymPy reduced the difference between the two sides to zero. Checked independently: a separate
method, named above, confirmed it. Checked numerically: the two sides agree at every sampled point, which is evidence,
not proof. Reviewed: a model or a person read it; that is all a sentence can have. Solution by
generator:structured/riemann_sums, checked 2026-10-13 with SymPy 1.14.0.